Vertex = (0, 0)
focus = (-2, 0)
p = -2 - 0 = -2
Required equation is (y - k)^2 = 4p(x - h); where (h, k) = (0, 0), the vertex
(y - 0)^2 = 4(-2)(x - 0)
y^2 = -8x
Required equation in standard form is x = -1/8 y^2
The answer it’s a. Pretty sure if not sorry
Answer:
first box 9.6 2nd box 7.2 third box 12
Step-by-step explanation:
9.6 is the missing height 12 is the hypotenuse is always last
A) Isolate y in both inequalities
1) x + y ≥ 4 => y ≥ 4 - x
2) y < 2x - 3
B) Draw the lines for the following equalities:
1) y = 4 - x
2) y = 2x - 3
C) Shade the regions of solutions
1) The region that is over the line y = 4 - x
2) The region that is below the line y = 2x - 3
The solution is the intersection of both regions; this is the sector between both lines that is to the right of the intersection point, including the portion of the very line y = 4 - x and excluding the portion of the very line y = 2x - 3
Answer: but will soon find out
Step-by-step explanation:
