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77julia77 [94]
3 years ago
5

What is 8.275 rounded to the nearest ounce?​

Mathematics
2 answers:
max2010maxim [7]3 years ago
5 0

Answer:8.0

Step-by-step explanation:

Crank3 years ago
3 0

Answer:

8.0

Step-by-step explanation:

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There isn't enough information to solve this problem we need to know how long the fence is
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Which step will get you closest to the solution of this equation?<br><br> 5⋅(x−2)=7
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When you divide both sides by 5
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2 years ago
Assume that foot lengths of women are normally distributed with a mean of 9.6 in and a standard deviation of 0.5 in.a. Find the
Makovka662 [10]

Answer:

a) 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b) 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c) 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 9.6, \sigma = 0.5.

a. Find the probability that a randomly selected woman has a foot length less than 10.0 in

This probability is the pvalue of Z when X = 10.

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 9.6}{0.5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

So there is a 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b. Find the probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

This is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 8.

When X = 10, Z has a pvalue of 0.7881.

For X = 8:

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 9.6}{0.5}

Z = -3.2

Z = -3.2 has a pvalue of 0.0007.

So there is a 0.7881 - 0.0007 = 0.7874 = 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c. Find the probability that 25 women have foot lengths with a mean greater than 9.8 in.

Now we have n = 25, s = \frac{0.5}{\sqrt{25}} = 0.1.

This probability is 1 subtracted by the pvalue of Z when X = 9.8. So:

Z = \frac{X - \mu}{s}

Z = \frac{9.8 - 9.6}{0.1}

Z = 2

Z = 2 has a pvalue of 0.9772.

There is a 1-0.9772 = 0.0228 = 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

5 0
3 years ago
Find the matrices of the following linear transformations
Sidana [21]

Answer:

The matrixes are in the explanation box.

1. A mapping of (x,y,z) to (x,y,0)

2. Is a mapping of (x,y,z) to (-x,-y,z)

Step-by-step explanation:

We have the orthogonal projection onto the cy-plane to be a mapping of (x,y,z) to (x,y,0). Then we will have a transformation matrix that has the form below.

[1 0 0]

[0 1 0]

[0 0 1]

For the reflection in the z-axis,it is a reflection of (x,y,z) to (-x,-y,z). Our matrix will then have the form below

[-1 0 0]

[0 -1 0]

[0 0  1]

4 0
2 years ago
Please help and show step by step pls
Brut [27]

First notice that

<em>x</em> ² + 5<em>x</em> + 6 = (<em>x</em> + 3) (<em>x</em> + 2)

so you can rewrite everything with a common denominator:

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 / (<em>x</em> + 2) = 6 / (<em>x</em> + 3)

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 (<em>x</em> + 3) / ((<em>x</em> + 2) (<em>x</em> + 3)) = 6 (<em>x</em> + 2) / ((<em>x</em> + 3) (<em>x</em> + 2))

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 (<em>x</em> + 3) / (<em>x</em> ² + 5<em>x</em> + 6) = 6 (<em>x</em> + 2) / (<em>x</em> ² + 5<em>x</em> + 6)

(5 + 7 (<em>x</em> + 3)) / (<em>x</em> ² + 5<em>x</em> + 6) = 6 (<em>x</em> + 2) / (<em>x</em> ² + 5<em>x</em> + 6)

As long as <em>x</em> ≠ -3 or <em>x</em> ≠ -2, the denominators are never zero, so we can cancel them and be left with

5 + 7 (<em>x</em> + 3) = 6 (<em>x</em> + 2)

Solving for <em>x</em> is easy from here:

5 + 7<em>x</em> + 21 = 6<em>x</em> + 12

7<em>x</em> - 6<em>x</em> = 12 - 5 - 21

<em>x</em> = -14

3 0
2 years ago
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