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saveliy_v [14]
3 years ago
6

PLEASE HELP WILL GIVE BRAINLIEST!!!!

Mathematics
2 answers:
finlep [7]3 years ago
7 0

Answer:

Make a graph

Step-by-step explanation: In order to plot points, you need to first make a graph. So you would make a graph and plot out the numbers on the line. Hopefully you know how to setup a graph and what goes on the x and y axis. So for the first one you would go left on the graph till you hit -3 and then down to -2 and then draw a point right there. For the second one you would go right to 2 and then up 4 and draw a point.

Tju [1.3M]3 years ago
3 0
Use (x,y) x=-3 y=-2 and x=2 y=4. Horizontal line is the x axis and vertical line is the y axis, look for -3 on the x axis and go down 2 to -2 that’ll be one point and do the same for ( 2,4). To find the length count how many squares there is to get to the next point.
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Corresponding solution for 3x-3(x+1)=3 plzzz answer quickly ​
Gekata [30.6K]
3x - 3(x + 1) = 3 \\ = > - 3(x + 1) = 3 - 3x \\ = > - 3(x + 1) = - 3(1 + x) \\

Hence,

x is cutting each other in this equation.

So, x can be of any value.i.e.,infinite.

Hope this will help you. 

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6 0
3 years ago
Bobby has a bag containing 2 sizes of marbles. The big ones weigh 10 g and the small ones weigh 3 g. If there are three times as
Vikentia [17]

Answer:

There are 19 big marbles

Step-by-step explanation:

10a + 3b = 209

a = 3b

3b = 3b

10a + a = 209

11a = 209

a = 209/11

a = 19

8 0
3 years ago
How do I solve ?? It’s cylinders
UkoKoshka [18]
V= 3.14r^2h
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3 0
3 years ago
Suppose that 4 fair coins are tossed. Let Equals The event that exactly 2 coins show tails and Equal The event that at least 2 c
faust18 [17]

Answer:

a) P ( E | F ) = 0.54545

b) P ( E | F' ) = 0

Step-by-step explanation:

Given:

- 4 Coins are tossed

- Event E exactly 2 coins shows tail

- Event F at-least two coins show tail

Find:

- Find P ( E |  F )

- Find P ( E | F prime )

Solution:

- The probability of head H and tail T = 0.5, and all events are independent

So,

                    P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT)  = 6*(1/2)^4 = 0.375

                    P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)

      = 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875

- The probabilities for each events are:

                    P ( E ) = 0.375

                    P ( F ) = 0.6875

- The Probability to get exactly two tails given that at-least 2 tails were achieved:

                    P ( E | F ) = P ( E & F ) / P ( F )

                    P ( E | F ) = 0.375 / 0.6875

                    P ( E | F ) = 0.54545

- The Probability to get exactly two tails given that less than 2 tails were achieved:

                    P ( E | F' ) = P ( E & F' ) / P ( F )

                    P ( E | F' ) = 0 / 0.6875

                    P ( E | F' ) = 0                

6 0
3 years ago
The parabola below is a graph of the equation, -y+x=-4. Which of the points satisfy the inequality, -y+x ≤ -4 ? Check all that a
Bad White [126]
POINTED 6 CAYUSE ISV VERTICVAL

8 0
3 years ago
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