Simplify

mash [69]

$Use\ (a^n)^m=a^{nm}\\\\(q^{10})^3=q^{10\cdot3}=q^{30}$

4 0

3 years ago

Three of the expressions will give the amount that remains after t years of a certain radioactive substance. Which expression is

MakcuM [25]

Answer:

The answer is D

Step-by-step explanation:

4 0

4 years ago

If you have a list of all three digit numbers that can be written using only the digits 1,2,3,4, and 5.

Yuri [45]

Answer:

61/125 or 0.488

Step-by-step explanation:

Total = 5×5×5 = 125

Numbers with no 4 = 4×4×4 = 64

Atleast one 4= 125-64 = 61

P(atleast one 4) = 61/125 or 0.488

8 0

3 years ago

Read 2 more answers

Need help please I'm on a time limit

amm1812

U have to do 4.50 x .30 and thats 1.35 so subtract that by original amount and its 3.15

8 0

4 years ago

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 55 o

Usimov [2.4K]

Answer:

a) For this case and using the empirical rule we can find the limits in order to have 9% of the values:

$\mu -2\sigma = 55 -2*6 =43$

$\mu +2\sigma = 55 +2*6 =67$

95% of the widget weights lie between 43 and 67

b) For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

$100 -0.15-2.5 = 97.85$

c) We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

Step-by-step explanation:

For this case our random variable of interest for the weights is bell shaped and we know the following parameters.

$\mu = 55, \sigma =6$

We can see the illustration of the curve in the figure attached. We need to remember that from the empirical rule we have 68% of the values within one deviation from the mean, 95% of the data within 2 deviations and 99.7% of the values within 3 deviations from the mean.

Part a

For this case and using the empirical rule we can find the limits in order to have 9% of the values:

$\mu -2\sigma = 55 -2*6 =43$

$\mu +2\sigma = 55 +2*6 =67$

95% of the widget weights lie between 43 and 67

Part b

For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

$100 -0.15-2.5 = 97.85$

Part c

We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

4 0

4 years ago