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2 years ago

8

Two water pumps are filling a pool. One of the pumps is high power and can fill the pool 5 hours before the other can do. Howeve

r, they both working together can fill half of the pool in 3 hours. In how many hours the high power pump can fill the pool?

1 answer:

beks73 [17]2 years ago

6 0

Answer:

add here be back charger

Step-by-step explanation:

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Why are convenience samples are not desirable?

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The disadvantages: Convenience samples do not produce representative results. If you need to extrapolate to the target population, convenience samples aren't going to get you there. ... Much larger convenience samples are not more accurate than small probability samples.

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2 years ago

Va rog mult sa ma ajutati ,imi trebuie neaparat . plz

Natasha_Volkova [10]

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amenda. de ce ai nevoie?

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2 years ago

Help plz:))) I’ll mark u brainliest

Papessa [141]

Answer:

25x = 75 (Because they are alternate interior angles)

=> x = 75/25

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So, x = 3

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3 years ago

Read 2 more answers

Solve the equation 2 sec² x = 3 - tan x for the domain 0° ≤ x ≤ 360°

vodka [1.7K]

$2 \sec^2 x = 3- \tan x \\\\\implies 2(1 +\tan^2 x) = 3- \tan x \\\\\implies 2 + 2 \tan^2 x +\tan x -3 =0\\\\\implies 2 \tan^2 x + \tan x -1 =0\\\\\implies 2u^2 + u -1 =0~~~ ;[\text{set} \tan x = u]\\\\\implies u = \dfrac{-1\pm \sqrt{1-4\cdot 2 \cdot (-1)}}{2(2)}\\\\\implies u =\dfrac{-1 \pm\sqrt{9}}{4}\\\\\implies u = \dfrac{-1 \pm 3}{4}\\\\\implies u = \dfrac{2}{4}=\dfrac 12~~ \text{or} ~~u =\dfrac{-4}{4} =-1\\\\$

$\implies \tan x = \dfrac 12 ~~ \text{or} ~~ \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\$

$x=\tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,} ~~x=\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\$

$\text{In degrees,}~ x = 135^{\circ},~315^{\circ},~\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]$

4 0

2 years ago

Three consecutive even numbers add up to 36. Select all of the following equations that will find the lowest number of the three

Misha Larkins [42]

Equation A find the lowest number of the three. Equation A satisfies the given conditions.

<h3>What is even number? </h3>

If the number is divisible by 2 then the number will be an even number. Similarly, the number is not divisible by 2 then the number will be an odd number.

Assume the three consecutive integers are 2x,2x+2,2x+4

The sum of the three consecutive even numbers are 36;

x+x+2+x+4 = 36

3x+6=36

3x=30

x=10

The three integers are found as;

x =10

x+2 = 10+2 = 12

2x+4 =10+4=14

Hence, equation A find the lowest number of the three. Equation A satisfies the given conditions.

To learn more about the even number, refer to the link;

brainly.com/question/2289438

#SPJ1

5 0

2 years ago