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ZanzabumX [31]
3 years ago
6

Liliana wants to write an equivalent expression for n+3-5n+6.

Mathematics
2 answers:
Anastaziya [24]3 years ago
5 0

Answer:

n=9/4

Step-by-explanation:

Equate the equation to zero

n+3-5n+6=0

Collect like terms

n-5n+3+6=0

-4n+9=0

Add 4n to both sides

9=4n

Divide both sides by 4

n=9/4

sammy [17]3 years ago
4 0

Answer:

Step-by-step explanation:

n +3 - 5n + 6 = n - 5n + 3 +6

= -4n + 9

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Sveta_85 [38]

Answer:5 or 5 degrees

Step-by-step explanation:

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3 years ago
Read 2 more answers
A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg
polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

P(X = x) = nCx p^{x} q^{n - x}

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662

Finally, the probability that 2 or fewer students will withdraw is

P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355

b) Compute the probability that exactly 4 will withdraw.

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0
4 years ago
In a pizza restaurant, you can get a basic pizza with two toppings: cheese and tomato.
poizon [28]

The number of different topping combination illustrates combination

Ross have 6 different topping combination to select from

<h3>The number of different combination</h3>

The given parameters are:

Extra toppings, n = 4

Toppings to select, r = 2

The number of extra topping that Ross can select is then calculated  using the following combination formula

Toppings = nCr

This gives

Toppings = 4C2

Evaluate the combination expression

Toppings = 6

Hence, Ross have 6 different topping combination to select from

Read more about combination at:

brainly.com/question/11732255

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