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erastova [34]
2 years ago
14

NO LINKS OR ASSESSMENT!!!Part 2: Domain and Range of Graphs​

Mathematics
1 answer:
wolverine [178]2 years ago
8 0
  • Domain is the set of input values
  • Range is the set of output value
  • Function is passes the vertical line test
<h3>#2</h3>

<u>Domain:</u>

  • - 2 ≤ x < 2 or x∈ [-2, 2)

<u>Range:</u>

  • -4 ≤ y < 0 or y ∈ (-4, 0]

<u>Function:</u>

  • YES - passes the vertical line test
<h3>#4</h3>

<u>Domain:</u>

  • - 0 ≤ x < 4 or x∈ [0, 4)

<u>Range:</u>

  • -2 < y < 2 or y ∈ (2, 2)

<u>Function:</u>

  • N0- doesn't pass the vertical line test
<h3>#6</h3>

<u>Domain:</u>

  • - 4 < x < 4 or x∈ (-4, 4)

<u>Range:</u>

  • -4 < y ≤ -2 or y ∈ (-4, -2]

<u>Function:</u>

  • YES - passes the vertical line test
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Solve (x+3) / 3x > 2 . [I guess 3x divides (x+3) and not 3], if so, then
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3 years ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS MATH QUESTION RIGHT NOOOO SCAMS PLEASE AND PLEASE EXPLAIN WHY THAT IS THE ANSWER
Komok [63]

Answer:

C

Step-by-step explanation:

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8 0
2 years ago
Please answer right away
Ilya [14]

Answer:

6.13

Step-by-step explanation:

Using Sine Law we know that

\dfrac{a}{SinA}=\dfrac{b}{SinB}=\dfrac{c}{SinC}

Using your figure let's assign sides and angles:

A=? B = 60° C = 70°

a = 5 b = ? c = x

If we put that into our formula:

\dfrac{5}{Sin?}=\dfrac{?}{Sin60}=\dfrac{x}{Sin70}

Notice that we have too many unknowns. We need to complete at least one ratio to do this, so how do we do this?

Notice we have 2 angles given, so we solve for the third angle. The sum of all angles in any triangle is always 180°

∠A + ∠B + ∠C= 180°

∠A + 60° + 70° = 180°

∠A + 130° = 180°

∠A = 180° - 130°

∠A = 50°

Now we can use this to solve for x.

\dfrac{5}{Sin50}=\dfrac{x}{Sin70}\\\\\dfrac{(5)(Sin70)}{Sin50} = x\\\\\dfrac{4.6985}{0.7660}=x\\\\6.1338 =x

So the closest answer would be 6.13

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Sphinxa [80]

Answer:

Factor x^{4}−2401

x^{4}−2401

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What is the value of x and y
Marina CMI [18]

Answer:

The answer is soooo simple

Step-by-step explanation:

its c

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