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katrin2010 [14]
2 years ago
10

My friend recently proved 0=1 and i know something is wrong but i dont know what

Mathematics
2 answers:
konstantin123 [22]2 years ago
5 0

Step-by-step explanation:

Remember when expanding radicals,

\sqrt{ab}  =  \sqrt{a}  \times  \sqrt{b}

When expanding radicals into two radicals, we don't let our radicand have two negative answers.

i  =  \sqrt{ - 1}

{i}^{2}  =  - 1

We don't do this

(\sqrt{ - 1} ) {}^{2}  =  \sqrt{ - 1 \times  - 1}

- 1 =  \sqrt{1}

- 1 = 1

Lina20 [59]2 years ago
4 0

√a × √b = √ab

only if at atleast one among a,b is positive

here both a,b is non negative so not possible

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Answer:

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Step-by-step explanation:

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3 years ago
The equations in this sytem were added to solve for x. What is the value of x?
son4ous [18]

<em><u>Question:</u></em>

The equations in this system were added to solve for x. What is the value of x? -2x+y=8 5x-y=-5 3x=3

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<em><u>Answer:</u></em>

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<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

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