Question

My friend recently proved 0=1 and i know something is wrong but i dont know what

Answer 1

Step-by-step explanation:

Remember when expanding radicals,

$\sqrt{ab} = \sqrt{a} \times \sqrt{b}$

When expanding radicals into two radicals, we don't let our radicand have two negative answers.

$i = \sqrt{ - 1}$

${i}^{2} = - 1$

We don't do this

$(\sqrt{ - 1} ) {}^{2} = \sqrt{ - 1 \times - 1}$

$- 1 = \sqrt{1}$

$- 1 = 1$

Answer 2

√a × √b = √ab

only if at atleast one among a,b is positive

here both a,b is non negative so not possible