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miv72 [106K]
3 years ago
7

What is a differential equation

Mathematics
1 answer:
pickupchik [31]3 years ago
5 0
A differential equation is one that contains the derivative of a function.  For example f(x) + 3 = 4f'(x) - 2.  Usually you will be given one of the functions and initial conditions if you have to solve.
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The ratio of the number of volleyball to the number of basketballs in the P.E room is 4:7 .there are 21 basketballs . How many v
densk [106]
Let volleyball be v and let basketball be b.

v : b = 4 : 7,      b = 21

v : 21 = 4 : 7

v/21 = 4/7

7*v = 4*21

v = 4*21/7

v = 4*3

v = 12

Volleyballs are 12

Hope this helps.
8 0
3 years ago
Evaluate i^31 please help
Nadya [2.5K]

ANSWER

{i}^{31}  =  - i

EXPLANATION

We want to evaluate

{i}^{31}

Use indices to rewrite the expression as:

=  {i}^{30}  \times i

We know that

{i}^{2}  =  - 1

So we rewrite the expression to obtain;

=  ({ {i}^{2}) }^{15}  \times i

This gives us;

=   {( - 1) }^{15}  \times i

This simplifies to

=  - 1 \times i

=  - i

4 0
3 years ago
1. {26, 69, 30, 27, 19, 54, 27}<br><br> Mean: <br> , Median: <br> , Mode: <br> , Range:
den301095 [7]

Answer:

Mean:36

Median:27

Mode:27

Range:50

Step-by-step explanation:

Mean: 19+26+27+27+30+53+69/7=36

Median: The middle number in the sequence when arranged in ascending order which is 27

Mode: The number that appeared more than others which is 27

Range: This is the difference between the largest number and the lowest number in the sequence which is 50.

IF THIS HELPS PLEASE MARK ME AS BRAINLIEST

5 0
2 years ago
Solve 15 ≥ -3x or 2/3 x ≥ -2.
hjlf
Solve each of the equations independently, then determine if the are continuous or discontinuous. 
15≥-3x [start here]
-5≤x    [divide both sides by (-3). *Dividing by a negative number means the direction of the sign changes!]
x≥-5  [just turned around for analysis]

Next equation:
2/3x≥-2    [start here]
x≥-2(3/2)  [multiply both sides of the equation by the reciprocal, 3/2)
x≥-3

So, (according to the first equation) all values of x must be greater than, or equal to -5.

(According to the second equation) all values of x must be greater than, or equal to -3. 
So, when graphed on a number line, both equations graph in the same direction, so they are continuous.

4 0
3 years ago
Read 2 more answers
Evaluate the spherical coordinate integral
expeople1 [14]

Rewrite the equations of the given boundary lines:

<em>y</em> = -<em>x</em> + 1  ==>  <em>x</em> + <em>y</em> = 1

<em>y</em> = -<em>x</em> + 4  ==>  <em>x</em> + <em>y</em> = 4

<em>y</em> = 2<em>x</em> + 2  ==>  -2<em>x</em> + <em>y</em> = 2

<em>y</em> = 2<em>x</em> + 5  ==>  -2<em>x</em> + <em>y</em> = 5

This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.

Compute the Jacobian determinant for this change of coordinates:

J=\begin{bmatrix}\frac{\partial u}{\partial x}&\frac{\partial u}{\partial y}\\\frac{\partial v}{\partial x}&\frac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&1\\-2&1\end{bmatrix}\implies|\det J|=3

Rewrite the integrand:

-3x+4y=-3\cdot\dfrac{u-v}3+4\cdot\dfrac{2u+v}3=\dfrac{5u+7v}3

The integral is then

\displaystyle\iint_R(-3x+4y)\,\mathrm dx\,\mathrm dy=3\iint_{R'}\frac{5u+7v}3\,\mathrm du\,\mathrm dv=\int_2^5\int_1^45u+7v\,\mathrm du\,\mathrm dv=\boxed{333}

5 0
3 years ago
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