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Rashid [163]
2 years ago
8

Indicate the method you would use to prove the two Δ's ≅ . If no method applies, enter "none".

Mathematics
1 answer:
Ghella [55]2 years ago
7 0

Answer: The answer is ASA I got it right

Step-by-step explanation:

brainliest pls <3

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2+4(x+1)-x<br>2+4x+-x<br>6+4x-x<br>6+3x​
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What is your question

Step-by-step explanation:

5 0
2 years ago
The given line passes through the points (−4, −3) and (4, 1).
dimulka [17.4K]
1+3/4+4
4/8
1/2
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5 0
3 years ago
I need help pls someone:(
Svetlanka [38]

Answer:

7/30

Step-by-step explanation:

3 0
3 years ago
The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
jeyben [28]

Answer:

The period of Y increases by a factor of k^ {3/2} with respect to the period of X

Step-by-step explanation:

The equation T ^ 2 = a ^ 3 shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?  

For the planet Y:  

T_y ^ 2 = a_y ^ 3

For planet X:  

T_x ^ 2 = a_x ^ 3

To know the factor of aumeto we compared T_x with T_y

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:  

a_y ^ 3 = (a_xk) ^ 3

So

\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x

Then, the period of Y increases by a factor of k^ {3/2} with respect to the period of X



4 0
3 years ago
HELPPPPPPPPPPPPPPPPP
Svetllana [295]

Answer:

I won't help you because by the looks of it you are cheating so figure it out yourself

Step-by-step explanation:

lol

4 0
3 years ago
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