Answer:
A
Step-by-step explanation:
The solution is at the points of intersections of the graphs
The graphs intersect at (- 3, 0 ) and (2, 5 ) , then
solutions are (- 3, 0 ) and (2, 5 )
This is supposed to be a question…????
Vertex form:
y-k=a(x-h)^2
h=-2,k=-20,y=-12 when x=0
thus;
-12+20=a(0+2)^2
8=4a
a=2
Equation:
y+20=2(x+2)^2
y+20=2(x^2+4x+4)
f(x)=2(x^2+4x+4)-20
f(x)=2x^2+8x+8-20
f(x)=2x^2+8x-20
$2.99 + 7% of $2.99 =
= $2.99 + 7% * $2.99
= $2.99 + 0.07 * $2.99
= $2.99 + $0.21
= $3.20