A^-4 is the question and it wants me to write in exponential notation with positive exponents

What is the value of n?<br><br> 40= -5n/8<br><br> n=________

vodka [1.7K]

40 = -5 × $\frac{n}{8}$

First, simplify 5 × $\frac{n}{8}$ to $\frac{5n}{8}$ / Your problem should look like: 40 = $-\frac{5n}{8}$
Second, multiply both sides by 8. / Your problem should look like: 320 = -5n
Third, divide both sides by -5. / Your problem should look like: $\frac{320}{-5}$ = n
Fourth, simplify $\frac{320}{-5}$ to $- \frac{320}{5}$ / Your problem should look like: $-\frac{320}{5}$ = n
Fifth, simplify $\frac{320}{5}$ to 64. / Your problem should look like: -64 = n
Sixth, switch sides. / Your problem should look like: n = -64

Answer: n = -64

7 0

3 years ago

Read 2 more answers

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .