Answer:
the confidence interval for the true weight of the specimen is;
4.1593 ≤ μ ≤ 4.1611
Step-by-step explanation:
We are given;
Standard deviation; σ = 0.001
Sample size; n = 8
Average weight; x¯ = 4.1602
We are given a 99% confidence interval and the z-value at this interval is 2.576
Formula for confidence interval is;
CI = x¯ ± (zσ/√n)
Plugging in the relevant values, we have;
CI = 4.1602 ± (2.576 × 0.001/√8)
CI = 4.1602 ± 0.000911
CI = (4.1602 - 0.000911), (4.1602 + 0.000911)
CI ≈ (4.1593, 4.1611)
Thus, the confidence interval for the true weight will be expressed as;
4.1593 ≤ μ ≤ 4.1611
Where μ represents the true weight
Answer: 61.16 ft
Step-by-step explanation:
We can think in this situation as a triangle rectangle.
where:
The height of the tree is one cathetus
The shadow of the tree is the other cathetus.
We know that the angle of elevation of the sun is 78°, an angle of elevation is measured from the ground, then the adjacent cathetus to this angle is the shadow of the tree. And the opposite cathetus will be the height of the tree.
Now we can remember the relationship:
Tg(A) = (opposite cathetus)/(adjacent cathetus)
Where:
A = 78°
Adjacent cathetus = 13ft
opposite cathetus = height of the tree = H
Then we have the equation:
Tg(78°) = H/13ft
Tg(78°)*13ft = H = 61.16 ft
There are 187 nickels and 66 dimes in the jar.
Step-by-step explanation:
Given,
Total coins = 253
Value of coins = $15.95 = 15.95*100 = 1595 cents
Value of each nickel = 5 cents
Value of each dime = 10 cents
According to given statement;
x+y=253 Eqn 1
5x+10y=1595 Eqn 2
Multiplying Eqn 1 by 5
Subtracting Eqn 3 from Eqn 2
Dividing both sides by 5
Putting y=66 in Eqn 1
There are 187 nickels and 66 dimes in the jar.
Keywords: linear equation, elimination method
Learn more about elimination method at:
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Answer:
y < 4
Step-by-step explanation:
Since the line is dotted, it will be either greater than or less than depending on if it is shaded above or below. It's "y" because the line crosses the y axis, not the x axis.
We calculate it by multiplying the place value and face value of the digit. For instance: If we consider a number 45. Here the digit 4 is in the tens column.
