Question

Use Gauss-Jordan elimination to solve the following linear system.

Answer 1

Answer:

The correct option is C) (4,4)

Step-by-step explanation:

Given linear system is :

$-x+6y=20$

$-x+3y=8$

Solve using Gauss - jordan elimination

It is an algorithm that can be used to solve systems of linear equations and to find the inverse of any invertible matrix.

$\:\begin{pmatrix}-1&6&20\\ \:-1&3&8\end{pmatrix}$

$\mathrm{Reduce\:matrix\:to\:row\:echelon\:form}\:\begin{pmatrix}a&\cdots &b\\ 0&\ddots &\vdots \\ 0&0&c\end{pmatrix}$

Divide row(1) by -1

$\begin{pmatrix}1&-6&-20\\ \:-1&3&8\end{pmatrix}$

Add row(1) to row(2)

$\begin{pmatrix}1&-6&-20\\ \:0&-3&-12\end{pmatrix}$

Divide row(2) by -3

$\begin{pmatrix}1&-6&-20\\ \:0&1&4\end{pmatrix}$

Add (6 * row(2) ) to row(1)

$=\begin{pmatrix}1&0&4\\ 0&1&4\end{pmatrix}$

Hence the corresponding values of x and y are (4, 4)

Therefore, the correct option is C) (4,4)

Answer 2

The answer would be C. (4,4)