Answer:
Step-by-step explanation:
AC = length of flagpole = 12 ft
AB = length of shadow = 14 ft
BC = length from the top of the flagpole to the end of the shadow = x ft
Use Pythagorean theorem to find the length of x,
x² = AC² + BC²
= 12² + 14²
= 144 + 196
= 340
x = √340
x = 18.4 ft
9514 1404 393
Answer:
55,637.8 square inches
Step-by-step explanation:
We can find side n using the Law of Sines:
n/sin(N) = p/sin(P)
n = p(sin(N)/sin(P)) = 600·sin(64°)/sin(96°)
n ≈ 542.246913 . . . . inches
The angle O is ...
O = 180° -N -P = 180° -64° -96° = 20°
Then the area is ...
A = 1/2·np·sin(O)
A = (1/2)(542.246913 in)(600 in)·sin(20°) ≈ 55,637.81008 in²
The area of ∆NOP is about 55,637.8 in².
Answer:
a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.
Step-by-step explanation:
For the same home (x1 is the same), x2 = 1 if it is on a busy street and x2 = 0 if it is not on a busy street. If x2 = 1, the value of 't' decreases by 3.6 when compared to the value of 't' for x2=0. Since 't' is given in thousands of dollars, when a home is on a busy street, its value decreases by 3.6 thousand dollars.

Therefore, the answer is a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.
divide both sides by 7 to get x alone
84/7 = 12
B.12