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3 years ago

13

A car mechanic borrow $7000 for 12 months at 13% interest rate the monthly payments are $817.43 what is the total amount includi

ng interest (repayment), that the mechanic paid for loan

1 answer:

hoa [83]3 years ago

3 0

It is 90,0000000000000000000000

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AB lies on a number line. The coordinate of point A is -6. Given that AB=20, what are two possible coordinates for point B?

Dafna1 [17]

Answer:

<em>-26 or 14</em>

Step-by-step explanation:

Given that

Coordinate of point A is -6.

Length of AB = 20

To find:

Coordinates for the point B = ?

Solution:

We are given that:

AB = 20

In other words, we can use modulus function to define the distance between A and B:

|Coordinates of B - Coordinates of A| = 20

Let the coordinates of B = $x$

Kindly refer to the attached image for the given situation.

Point B might be either on the left or on the right side of A.

That means:

$|x-(-6)| = 20\\\Rightarrow |x+6|=20$

Now, let us have a look at the modulus function:

$|y|=\left \{ {-{y}\ if\ y0} \right.$

So,

$|x+6|=\left \{ {-{(x+6)}\ if\ (x+6)0} \right.$

$(x+6 ) =20\\\Rightarrow x =14$

$-(x+6 ) =20\\\Rightarrow x =-26$

Therefore, the answer is:

<em>-26 or 14</em>

4 0

3 years ago

What is the value of x??

Fudgin [204]

Answer:

x + 5 = 5×

7x - 5 = 2x

5x + 2x + x = 180

<u>8</u><u>×</u><u> </u> = 180

8 8

x = 22.5

3 0

2 years ago

In 1985, the cost of clothing for a certain familiy was $620. In 1995, 10 years later, the cost of clothing for this famility wa

Sholpan [36]

Answer:

$848

Step-by-step explanation:

Calculation for the cost of this familiy's clothing in 1991

First step is to calculate the amount that is increase per year

Increase per year= ($1000-$620)/(1995-1985)

Increase per year= 380/10

Increase per year= $38

Now let y be :38*x + $620 and let x be 6 years (1991-1985)

Second step is to calculate the cost of the clothing in 1991

y = 38*6 + 620

y=228+620

y = $848

Therefore the cost of this familiy's clothing in 1991 will be $848

6 0

3 years ago

A line, y = mx + b, passes through the point (10, 3) and is parallel to the line 2x+5y=12.

slava [35]

We have been given that a line $y=mx+b$ passes through the point (10, 3) and is parallel to the line $2x+5y=12$ . We are asked to find the y-intercept of the line.

First of all we will rewrite our given equation in slope-intercept form as:

$2x-2x+5y=12-2x$

$5y=-2x+12$

$\frac{5y}{5}=-\frac{2}{5}x+\frac{12}{5}$

$y=-\frac{2}{5}x+\frac{12}{5}$

We know that slope of parallel lines is equal, so slope of parallel line to our given line would be $-\frac{2}{5}$ .

Now we will use slope-intercept form of equation to find y-intercept.

$y=mx+b$ , where,

m = Slope,

b = The y-intercept.

Let us substitute $m=-\frac{2}{5}$ and coordinates of point $(10,3)$ in above equation as:

$3=-\frac{2}{5}(10)+b$

$3=-2(2)+b$

$3=-4+b$

$3+4=-4+4+b$

$7=b$

Therefore, the y-intercept is 7 and our required equation would be $y=-\frac{2}{5}x+7$ .

5 0

3 years ago

Please help with #12 im confused<br> that is the key but i dont get it

Svetllana [295]

Given Equation

$\boxed{ \tt \: (8 \sqrt{3} - 2 \sqrt{2} )(8 \sqrt{3} + 2 \sqrt{2})}$

Step by step expansion:

$\dashrightarrow \sf \: (8 \sqrt{3} - 2 \sqrt{2} )(8 \sqrt{3} + 2 \sqrt{2})$

$\\ \\$

$\dashrightarrow \sf \: (8 \sqrt{3})^{2} - (2 \sqrt{2} {)}^{2}$

Reason:

(a + b)(a - b) = a²- b²

$\\ \\$

$\dashrightarrow \sf \: (8 {}^{2} \times { \sqrt{3} }^{2} )- (2 \sqrt{2} {)}^{2}$

$\\ \\$

$\dashrightarrow \sf \: (64 \times 3 ) - (2 \sqrt{2} {)}^{2}$

$\\ \\$

$\dashrightarrow \sf \: (64 \times 3 ) - (2 {}^{2} \times \sqrt{2} {}^{2} {)}$

$\\ \\$

$\dashrightarrow \sf \: 192- 8$

$\\ \\$

$\dashrightarrow \sf \: 184$

$\\ \\$

~BrainlyVIP ♡

4 0

2 years ago

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