Answer:a = - 2
b = - 3
c = 3
Step-by-step explanation:
a + 5b - c = - 20 - - - - - - - - - 1
4a - 5b + 4c = 19 - - - - - - - - - 2
-a - 5b - 5c = 2 - - - - - - - - - - - 3
Adding equation 1 and equation 2, it becomes
- 6c = - 18
c = - 18/ - 6 = 3
Multiplying equation 2 by 1 and equation 3 by 4, it becomes
4a - 5b + 4c = 19
-4a - 20b - 20c = 8
Adding both equations, it becomes
- 25b - 16c = 27
- 25b = 27 + 16c = 27 + 16 × 3
- 25b = 75
b = 75/- 25 = - 3
Substituting b = - 3 and c = 3 into equation 1, it becomes
a + 5 × - 3 - 3 = - 20
a - 15 - 3 = - 20
a - 18 = - 20
a = - 20 + 18 = - 2
Answer:
(-5,-14)
Step-by-step explanation:
To find the solution of the system of two equations

equate right sides of these two equations:

Rewrite terms with x into the left side and without x into the right side:
![4x-2x=-4-6\\ \\2x=-10\ [\text{divide by 2}]\\ \\x=-5](https://tex.z-dn.net/?f=4x-2x%3D-4-6%5C%5C%20%5C%5C2x%3D-10%5C%20%5B%5Ctext%7Bdivide%20by%202%7D%5D%5C%5C%20%5C%5Cx%3D-5)
Substitute x=-5 into the first equation:

The solution is (-5,-14)
Answer: The answer is (D) prevent the passge of certian molecules into the cell.
Step-by-step explanation: We have four option out of which one describes the functions of protein present in the phospholipid bilayer in the cell membrane.
Phospholipid bilayers are critical components of cell membranes. Its function is to act as a barrier to the passage of molecules and ions into and out of the cell. It allows selective substances and molecules to come in and go out of the membrane.
Thus, the correct option is (D).
(1) y² + x² = 53
(2) y - x = 5 ⇒ y = x + 5
subtitute (2) to (1)
(x + 5)² + x² = 53 |use (a + b)² = a² + 2ab + b²
x² + 2x·5 + 5² + x² = 53
2x² + 10x + 25 = 53 |subtract 53 from both sides
2x² + 10x - 28 =0 |divide both sides by 2
x² + 5x - 14 = 0
x² - 2x+ 7x - 14 = 0
x(x - 2) + 7(x - 2) = 0
(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7
subtitute the values of y to (2)
for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3
Answer: x = 2 and y = 7 or x = -7 and y = 3