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notsponge [240]
3 years ago
6

The radius of a circle is 7cm. find it's area in terms of pi​

Mathematics
2 answers:
WITCHER [35]3 years ago
7 0
A= π(r)^2 so it would be A= π(7x7) and so A= π(49). Hope it helps :-)
Pepsi [2]3 years ago
7 0

Answer:

49π

Step-by-step explanation:

The formula for the area of a circle is \pi r^{2}.

When you insert the numbers, you get a=\pi *7^{2}

7^{2}     =49

<h3>When you put it all together, you get 49\pi</h3>

Hope this helped :)

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The midpoint QR is M (-1,2). One endpoint is R (3,4). Find the coordinates of the other endpoint.
butalik [34]

M = (x₁ + x₂)/2  , (y₁ + y₂)/2

(-1, 2) = \frac{3 + x}{2} , \frac{4 + x}{2}

At this point, it is easier to separate the x's and y's into two different equations:

x's: -1 = \frac{3 + x}{2}

     -2 = 3 + x

     -5 = x

y's: 2 = \frac{4 + x}{2}

     4 = 4 + x

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Answer: (-5, 0)

7 0
3 years ago
Help ASAP please
Agata [3.3K]

Answer:

55,000

Step-by-step explanation:

I already explained it on another problem but I'll show the equation again.

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7 0
3 years ago
A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time
user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

a(t) = 24t + 2

Velocity:

v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

v(t) = 12t^{2} + 2t + 13

Position:

s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K

Since s(0) = 3

s(t) = 4t^{3} + t^{2} + 13t + 3

What is its position at time t=5?

This is s(5).

s(t) = 4t^{3} + t^{2} + 13t + 3

s(5) = 4*5^{3} + 5^{2} + 13*5 + 3

s(5) = 593

It's position at time t = 5 is 593.

3 0
3 years ago
√50, √8, whats the area of the triangle no picture
Bas_tet [7]

Answer:

Area  = 10

Step-by-step explanation:

(\sqrt{50}×\sqrt{8})  ÷ 2 = 10

6 0
2 years ago
Which of the following transformations does not preserve distance and angle measures?
Sveta_85 [38]
D) horizontal stretch

hope it helps
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