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2 years ago

The radius of a circle is 7cm. find it's area in terms of pi

Mathematics

2 answers:

WITCHER [35]2 years ago

7 0

A= π(r)^2 so it would be A= π(7x7) and so A= π(49). Hope it helps :-)

Pepsi [2]2 years ago

7 0

Answer:

49π

Step-by-step explanation:

The formula for the area of a circle is $\pi r^{2}$ .

When you insert the numbers, you get $a=\pi *7^{2}$

$7^{2} =49$

<h3>When you put it all together, you get 49 $\pi$ </h3>

Hope this helped :)

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I need to find the answer to this question and please explain how.

deff fn [24]

Among the given statements, the true statements are:

If a number is divisible by 3 and 4, then it is divisible by 12.
The number 119 is a composite number.

In the question, we are asked for the true statements among the given options:

1. All even numbers are composite numbers.

Answer - False

Reason - 2 is an even number, which is not a composite number.

2. If a number is divisible by 3 and 4, then it is divisible by 12.

Answer - True

Reason - If any number, n, is divisible by any two numbers, x and y, then it is also divisible by their LCM, and the LCM of 3 and 4 is 12.

3. All prime numbers are odd numbers.

Answer - False

Reason - 2 is a prime number, which is not odd.

4. The number 119 is a composite number.

Answer - True

Reason - The number 119 is a composite number, as it is not a prime number, as it is divisible by 7 and 17 too, other than 1 and itself.

5. 12 is a factor of 6.

Answer - False.

Reason - When 6 is divided by 12, the integral quotient that we get is 0, and the remainder is 6, but for any number x, to be a factor of y, on dividing y by x, the remainder should be 0.

6. If a number is divisible by 6 and 4, then it is also divisible by 4.

Answer - False

Reason - If any number, n, is divisible by any two numbers, x and y, then it is also divisible by their LCM, and the LCM of 6 and 4 is 12.

Thus, a number divisible by 6 and 4 is divisible by 12 but not necessarily by 24. Example 12 is divisible by both 6 and 4 but not divisible by 24.

Thus, among the given statements, the true statements are:

If a number is divisible by 3 and 4, then it is divisible by 12.
The number 119 is a composite number.

Learn more about divisibility at

brainly.com/question/26789053

#SPJ9

8 0

1 year ago

Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x<6

Oksi-84 [34.3K]

Answer:

$-1/3$

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

$9x^2-15x$

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

$9x^2-15x=6$

Subtract 6 from both sides:

$9x^2-15x-6=0$

Divide everything by 3:

$3x^2-5x-2=0$

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

$3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0$

Find the x using the Zero Product Property:

$3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2$

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

$x=-1/3$

Assume that the correct symbol is >. Thus,

$x>-1/3$

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

$9x^2-15x$