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3 years ago

PLEASE HELP ME ASAP SHE SAID IT WASN'T B NOR C!!!!

Mathematics

2 answers:

garri49 [273]3 years ago

7 0

Yeah A might be it…this questions makes no sense if it’s the answer tho

Liula [17]3 years ago

4 0

Answer:

hmm try option a................

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Please may someone help with c

german

Step-by-step explanation:

Distance between two villages = d

$(a) \: \frac{4}{5} \: of \: d = \frac{4}{5} d \\ \\ (b) \: \frac{3}{4} \: of \: d = \frac{3}{4} d \\ \\ (c) \: \frac{4}{5} d - \frac{3}{4} d = 1.5 \\ \\ \therefore \: \bigg(\frac{4}{5} - \frac{3}{4} \bigg) d = 1.5 \\ \\ \therefore \: \bigg(\frac{4 \times 4 - 3 \times 5}{5 \times 4} \bigg) d = 1.5 \\ \\ \therefore \: \bigg(\frac{16- 15}{20} \bigg) d = 1.5 \\ \\ \therefore \: \bigg(\frac{1}{20} \bigg) d = 1.5 \\ \\ \therefore \: d = 1.5 \times 20 \\ \\ \: \: \: \: \: \huge \orange{ \boxed{{ \therefore \: d = 30}}}$

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3 years ago

How are renewable and nonrenewable resources different?

Zinaida [17]

Renewable resources can be replaced in a reasonable amount of time, but nonrenewable resources cannot.

Step-by-step explanation:

Nonrenewable resources can be depleted within a human lifespan while renewable resources cannot. An examp0le of a non-renewable resource is crude oil. With continuous mining of crude oil, the natural reserves will continue to decrease until it gets even harder and more expensive to find.

Renewable resources, however, are cannot be depleted since they are ever self-renewing. An example is a wind and the sun whose energy can be harnessed to provide energy to power homes and businesses.

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3 years ago

Read 2 more answers

A tank contains seven liters of 10% alcohol solution. how many liters of 6% alcohol should be added to have 8% alcohol solution?

kow [346]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive

VikaD [51]

Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

$\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}$

recall that

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}$

therefore, let's just plug that on the remaining ones,

$\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}$

now, let's rationalize the denominator on tangent and secant,

$\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}$

3 0

3 years ago

Show work please!...

Leni [432]

Answer:what goes around comes around

Step-by-step explanation:

"i need points too thanks"

7 0

3 years ago