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MA_775_DIABLO [31]
3 years ago
13

How to simplify (n+2)!/n! I will mark brainliest and give a thanks!

Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0
\dfrac{(n+2)!}{n!}=\dfrac{(n+2)(n+1)n!}{n!}=(n+2)(n+1)=n^2+3n+2
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Max is thinking of a number, which he calls n. He adds 8 and then doubles the sum. What is Max's final number if his starting nu
Sonja [21]

Based on the given situation, Max final number if his starting number is 7 is -4.5

<h3 /><h3>Algebra</h3>

  • Unknown number = n

  • He adds 8

n + 8

  • then doubles the sum

2(n + 8)

  • starting number = 7

So,

2(n + 8) = 7

2n + 16 = 7

2b = 7 - 16

2n = -9

n = -9/2

n = -4.5

Learn more about algebra:

brainly.com/question/4344214

#SPJ1

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2 years ago
A particular concentration of a chemical found in polluted water has been found to be lethal to 20% of the fish that are exposed
Ivahew [28]
B) Find the mean and variance of the number that survive
explanation:
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4 years ago
Find the area of a circle that has a 12 inch radius.
Mama L [17]
The area is 452.39 Hint : If you know the radius of a circle , you can use it to find the area of what that circle . Just plug that value into the formula for the area of a circle and solve . I hope that's help !
5 0
3 years ago
Read 2 more answers
5x-3x+7=3x-1<br><img src="https://tex.z-dn.net/?f=4r%20%2B%20%20%5Cfrac%7B2%7D%7B4%7D%20r%20%2B%2014%20%3D%205r%20-%20%20%5Cfrac
nirvana33 [79]

1). 5x-3x+7 = 3x-1

2x + 7 = 3x - 1

3x-2x=7+1

x=8

2)

4r +  \frac{2}{4} r + 14 = 5r -  \frac{3}{4} r + 1 - 3\\ \\5r-4r-\frac{3}{4} r -  \frac{2}{4} r = 14-1+3\\ \\r-\frac{5}{4}r =16\\ \\\frac{4}{4}r-\frac{5}{4}r =16\\ \\-\frac{1}{4}r=16\\ \\ r=-64

5 0
3 years ago
Which ordered pair is the solution to the system of equations?
prisoha [69]

Answer:

(3, -3)

Step-by-step explanation:

{у = 3х - 12

{4х + 6у = −6

4x + 6[3x - 12] = −6

4x + 18x - 72 = −6

−6 = −72 + 22x

+72 + 72

___________

66 = 22x

__ ___

22 22

3 = x [Plug this back into both equations above to get the y-coordinate of −3]; -3 = y

I am joyous to assist you anytime.

3 0
3 years ago
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