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Oliga [24]
3 years ago
10

On a six-question multiple-choice test there are five possible answers for each question, of which one is correct and four are i

ncorrect. If a student guesses randomly, find the probability of (a) being correct on three questions, (b) being correct on four questions, (c) being correct on all six questions.
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

Step-by-step explanation:

given that on a six-question multiple-choice test there are five possible answers for each question, of which one is correct and four are incorrect

By mere guessing probability for choosing correct answer = p = 0.2

also each question is independent of the other

Hence if X is the number of correct questions then

X is binomial with p = 0.2 and n = 6

a) being correct on three questions,

=P(X=3) = 0.08192

(b) being correct on four questions,

= P(X=4) = 0.01536

(c) being correct on all six questions

=P(x=6) = 0.000064

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Since we've drawn one now, there's only 21 - 1 = 20 total coins left. The probability of drawing a second quarter is: (4 - 1) / (21 - 1) = 3/20.

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