All categories

3 years ago

What is the answer to 10s+5-4s=23

Mathematics

2 answers:

amm18123 years ago

6 0

Answer:

s=3

Step-by-step explanation:

10s+5-4s=23

10s-4s=23-5

6s=18

s=18÷6

s=3

grigory [225]3 years ago

5 0

Answer:

Step-by-step explanation:

6s+5=23

6s=18

s=18/6

s=3

You might be interested in

I'm trying to find out the number of how much it cost to wrap each present, day one 41 small gifts were wrapped and 45 large wer

Licemer1 [7]

Answer:

Small gift: $2

Large gift: $7

Step-by-step explanation:

Let x represent cost of wrapping each small gift and y represent cost of wrapping each large gift.

We have been given that day one 41 small gifts were wrapped and 45 large were wrapped equaling $397.

We can represent this information in an equation as:

$41x+45y=397...(1)$

We are also told that day two 30 small gifts were wrapped and 47 large were wrapped equaling $389. We can represent this information in an equation as:

$30x+47y=389...(2)$

From equation (1), we will get:

$x=\frac{397-45y}{41}$

Upon substituting this value in equation (2), we will get:

$30(\frac{397-45y}{41})+47y=389$

$\frac{11910-1350y}{41}+\frac{47*41y}{41}=389$

$\frac{11910-1350y+1927y}{41}=389$

$\frac{11910+577y}{41}=389$

$\frac{11910+577y}{41}\cdot 41=389\cdot 41$

$11910+577y=15949$

$11910-11910+577y=15949-11910$

$577y=4039$

$\frac{577y}{577}=\frac{4039}{577}$

$y=7$

Therefore, cost to wrap a large gift is $7.

Upon substituting $y=7$ in equation $x=\frac{397-45y}{41}$ , we will get:

$x=\frac{397-45(7)}{41}$

$x=\frac{397-315}{41}$

$x=\frac{82}{41}$

$x=2$

Therefore, cost to wrap a small gift is $2.

8 0

3 years ago

Write an iterated integral for ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing Integral from no

coldgirl [10]

With the given order of integration, the interval over D is

$\displaystyle \iiint_D f(x,y,z) \, dV = \int_{-3}^{3} \int_{-\sqrt{9-x^2}}^{\sqrt{9-x^2}} \int_{-\sqrt{9-x^2-z^2}}^{\sqrt{9-x^2-z^2}} f(x,y,z) \, dy \, dz \, dx$

8 0

3 years ago

A kite is stuck in a 36-ft tree. If the angle of elevation from the kite and the ground is 12, find the length of the kite.

yanalaym [24]

Answer:

173.15 ft.

Step-by-step explanation:

Please find the attachment.

Let L be the length of kite.

We have been given that a kite is stuck in 36-ft tree. The angle of elevation from the kite and the ground is 12.

We can see from our attachment that kite and tree form a right triangle. height of tree is opposite of angle of elevation and length of kite is hypotenuse.

Since we know that Sine relates the opposite and hypotenuse of a right triangle, so we will use sine to find the length of kite.

$sin(12)=\frac{36}{L}$