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Elodia [21]
3 years ago
6

One day a retail store received a box of 24 shirts. If this shipment had 6 defective shirts, what can the store expect for upcom

ing shipments?
Mathematics
1 answer:
disa [49]3 years ago
5 0

Answer:

1 /4

Step-by-step explanation:

Given that:

Number of shirts in shipment = 24

Number of defective shirts in shipment = 6

The expectation about upcoming shipment which can be inferred from the information give is the probability of defect in upcoming shipments :

Probability of defect = Number of defect in shipment / total number of items in shipment

P(defect) = 6 /24 = 1 /4

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Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide
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The probability that Jenny gets to choose lunch is  64%  0.64 (rounded) or 0.636.

Work:

Number of roses and carnations divided by the total number of flowers

<span>7/11 = 0.636 = 0.64 (rounded)

once again same answer
</span><span /><span>
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What is the parent function of the following function?<br> f(x) = 3(5)*
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Read 2 more answers
Can someone help and explain and do the solution pls :(
brilliants [131]

Consider ∆JWZ and ∆JKZ

WZ~KJ (given)

<u>/</u><u> </u><u>WZJ</u>~<u>/</u><u> </u>KJZ (given)

JZ~JZ (common)

Therefore,

∆JWZ~∆JKZ by SAS congruence rule.

JW~ZK by CPCT.

6 0
2 years ago
Twin brothers, Billy and Bobby, can mow their grandparent’s lawn together in 63 minutes. Billy could mow the lawn by himself in
Pepsi [2]

Answer:

<h2>140 minutes</h2>

Step-by-step explanation:

this problem focuses on the combined work rate

both can finish the work under 63 minute

let bobby mow the lawn in x minute

Billy will then mow the lawn in x-25 minutes

Let the completed job = 1 (a mowed lawn)

we can now apply the combined work formula for the two boys as

\frac{63}{x}+\frac{63}{x-25}=1

multiplying through by x(x-25 )we have

63(x-25)+63x= x(x-25)

open bracket we have

63x-1575+63x= x^2-25x

rearranging and collecting like terms we have

0=x^2-25x-63x-63x+1575 \\\\0=x^2-151x+1575 \\\\x^2-151x+1575=0

we can now use the quadractic formula

x=\frac{-b\frac{+}{} \sqrt{b^2-4ac} }{2a}

 

a= 1

b= -151

c= 1575

x=\frac{-(-151)\frac{+}{} \sqrt{151^2-4*1*1575} }{2*1}

x=\frac{-(-151)\frac{+}{} \sqrt{22801-6300} }{2} \\\\x=\frac{-(-151)\frac{+}{} \sqrt{16501} }{2} \\\\x=\frac{-(-151)\frac{+}{} 128.45}{2} \\\\

x=\frac{-(-151)+128.45}{2} \\\\\x=\frac{279.45}{2} \\\\x=139.72 \\\\\\x=\frac{-(-151)-128.45}{2}\\\\x=\frac{151-128.45}{2}\\\\x=\frac{22.55}{2}\\\\x=11.27

the first answer x= 139.72 approximately 140 minutes mins is correct for  Bobby's time

let us check

\frac{63}{140}+\frac{63}{140-25}=1\\\\\\0.45+\frac{63}{115} =1\\\\0.45+0.5478=1\\0.997 =1

we can see that the solution approximates to 1

8 0
3 years ago
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