Question

Please help with algebra, 50 points to anyone who can answer!!

Answer 1

Answer:

let's solve them.

Step-by-step explanation:

1) go...

To find that

" After how many days is the revenue for each game the same "

we have to balance the two equations :

$m(x) = r(x) \\ {x}^{2} - 9x - 10 = 2x + 10$

subtract the sides of equation minus 10

${x}^{2} - 9x - 20 = 2x$

subtract the sides of equation minus 2x

${x}^{2} - 11x - 20 = 0$

now we have to find ∆ to can find the value of x

$∆ = {b}^{2} - 4ac \\ a = 1 \\ b = - 11 \\ c = - 20 \\ \\ ∆ = {11}^{2} - 4(1)( - 20) \\ \\ ∆ = 121 + 80 = 201$

To find the value of x we have this equation :

$x = \frac{ - b + \sqrt{∆} }{2a} \: and \: x = \frac{ - b - \sqrt{ ∆} }{2a} \\ x = \frac{11 + \sqrt{201} }{2} \: and \: x = \frac{11 - \sqrt{201} }{2} \\ x = \frac{11 + 14.18}{2} \: and \: x = \frac{11 - 14.18}{2} \\ x = \frac{25.18}{2} \: and \: x = \frac{ - 3.18}{2} \\ x = 12.59 \: and \: x = - 1.59$

we're done here.

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2) go...

I can just solve in one method.

First balance the equations to find when the ball and the rocket reach to the same height.

$b(t) = p(t) \\ - {t}^{2} - 2t + 36 = - 2t + 20$

subtract the sides of equation minus 20

$- {t}^{2} - 2t + 16 = - 2t$

subtract the sides of equation plus 2t

$- {t}^{2} + 16 = 0 \\ - {t}^{2} = - 16 \\ {t}^{2} = 16 \\ t = 4 \: acceptable \\ t = - 4 \: unacceptable \\ because \: time \: cannot \: be \: negative.$

So after 4 seconds the rocket and the ball reach to the same height.

And we're compeletly done.

good luck buddy ♥️♥️♥️♥️♥️.