Answer:
let's solve them.
Step-by-step explanation:
1) go...
To find that
" After how many days is the revenue for each game the same "
we have to balance the two equations :

subtract the sides of equation minus 10

subtract the sides of equation minus 2x

now we have to find ∆ to can find the value of x

To find the value of x we have this equation :

we're done here.
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2) go...
I can just solve in one method.
First balance the equations to find when the ball and the rocket reach to the same height.

subtract the sides of equation minus 20

subtract the sides of equation plus 2t

So after 4 seconds the rocket and the ball reach to the same height.
And we're compeletly done.
good luck buddy ♥️♥️♥️♥️♥️.