BRAINLIEST TO WHOEVER CAN HELP ME !!Select the correct statement about the function represented by the table.

Ellis is painting wooden fenceposts before putting them in his yard. They are each 5 feet tall and have a diameter of 1 foot. Th

Naya [18.7K]

Answer:

39.25 cubic feet of paint will be needed by Ellis.

Step-by-step explanation:

Volume of a cylinder:

The volume of a cylinder of radius r and height h is given by:

$V = \pi r^2h = 3.14r^2h$

How much paint will Ellis need to paint all the surfaces of the 10 fenceposts?

This is the combined volume of these 10 fenceposts.

They are each 5 feet tall and have a diameter of 1 foot.

Radius is half the diameter, so $r = \frac{1}{2} = 0.5$ . Also $h = 5$

10 fenceposts:

Each has the same volume, so:

$V = 10(3.14)r^2h = 31.4(0.5)^2(5) = 39.25$

39.25 cubic feet of paint will be needed by Ellis.

6 0

2 years ago

To drive to work, Dave has to drive 20 miles east and then 15 miles north. If there were a direct road going northeast, how many

suter [353]

By the Pythagorean theorem:

$x= \sqrt{20^2+15^2}= \sqrt{400+225}= \sqrt{625}=25 \ miles$

7 0

2 years ago

What are the dimensions (length and width) if the poster is enlarged by a factor of 1.5 ? (Remember multiply the factor by the d

Veseljchak [2.6K]

Use socratic or photomath

5 0

2 years ago

A rare form of malignant tumor occurs in 11 children in a million, so its probability is 0.000011. Four cases of this tumor occ

Shkiper50 [21]

Answer:

a) The mean number of cases is 0.14608 cases.

b) The probability that the number of cases is exactly 0 or 1 is 0.990.

c) The probability of more than one case is 0.010

d) No, because the probability of more than one case is very small

Step-by-step explanation:

We can model this problem with a Poisson distribution, with parameter:

$\lambda=r*t=0.000011*13,280=0.14608$

a) The mean amount of cases is equal to the parameter λ=0.14608.

b) The probability of having 0 or 1 cases is:

$P(k=0)=\frac{\lambda^0 e^{-\lambda}}{0!}=\frac{1*0.864}{1} =0.864\\\\ P(k=1)=\frac{\lambda^1 e^{-\lambda}}{0!}=\frac{0.14608*0.864}{1} =0.126\\\\P(k\leq1)=0.864+0.126=0.990$

c) The probability of more than one case is:

$P(k>1)=1-P(k\leq 1)=1-0.990=0.010$

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.

7 0

2 years ago

IM BEGGING YOU PLEASE HELP PLEASE HELP I NEED HELP PLEASE

I am Lyosha [343]

Answer:

area of shaded region: 21.07 ft²

Given for semi circle:

radius of semi-circle: 7 ft

Given for rectangle:

width: 7 ft
length: 14 ft

Find area of rectangle:

Length * Width

14 * 7

98 ft²

Find the area of semi circle:

1/2 * π * r²

1/2 * 3.14 * (7)²

76.93 ft²

Area of shaded region:

area of rectangle - area of semi-circle

98 ft² - 76.93 ft²

21.07 ft²

8 0

1 year ago