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2 years ago

2 friends share 7 cookies equally how many cookies does each person get

Mathematics

1 answer:

tester [92]2 years ago

5 0

3.5 cookies

Friend one: 3 Friend two: 3

One leftover cookie

Split in half give one to each and that makes 3.5

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How many real number solutions are there to the equation 0=-3x^2 + x -4

natta225 [31]

We have that
the equation
y=-3x² + x -4
the real number solutions are the points x intercept of the graph
are the points when y=0

using a graph tool
see the attached figure

the graph has no point of intersection with the x axis
therefore

the answer is
there are zero real numbers solutions

8 0

2 years ago

Graph Photo attached

Andreas93 [3]

$p(green) = \frac{no \: of \: green}{total \: } \\ p = \frac{8}{40} \times 100\% \\ p = 20\% \\$
option 2

3 0

3 years ago

Help please!!! Idk the answer.. if anyone knows then will u help me please!!! I will mark as BRAINLIEST

serious [3.7K]

Answer:

which one?

Step-by-step explanation:

7 0

2 years ago

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Abriana claims that the solution to the system of linear equations y = 2x – 1 and –12x + 3y = 9 is (–2, –5). Select all methods

EleoNora [17]

Answer:

Substitution method can be used

Step-by-step explanation:

Given the system of equations

y = 2x-1 ....1

-12x + 3y = 9 ....2

The best method to use id the substitution method

Substitute equation 1 into 2;

From 2;

-12x + 3y = 9

-4x + y = 3

-4x + 2x-1 = 3

-2x -1 = 3

-2x = 3+1

-2X = 4

x = -4/2

x = -2

Substitute x = -2 into 1

y = 2x - 1

y = 2(-2)-1

y = -4-1

y = -5

Hence the solution to the system of equation is (-2, -5)

7 0

2 years ago

What is the answer for this problem in the picture

DENIUS [597]

Answer:

The correct answer option is $= 8 x ^ 4 y z ^ 4 \sqrt{2yz}$ .

Step-by-step explanation:

We are given the following expression and we are to simplify it and determine whether which of the given expressions is equivalent to it, assuming $y\geq 0$ and $z\geq 0$ :

$\sqrt { 128 x ^ 8 y ^ 3 z ^ 9 }$

Breaking the terms to get:

$\sqrt { 128 x ^ 8 y ^ 3 z ^ 9 }$ $=8\sqrt{2yz} \times x^{8\times\frac{1}{2} } \times y^{2\times \frac{1}{2} } \times z^{8\times \frac{1}{2} }$

$= 8 x ^ 4 y z ^ 4 \sqrt{2yz}$

4 0

3 years ago

Read 2 more answers