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3 years ago

4 is 2% of what number?

Mathematics

2 answers:

Andreas93 [3]3 years ago

7 0

Answer:

4 is 2% of 200

Step-by-step explanation:

hope it helps :) good luck and have a great day/night! ❤️✨

EleoNora [17]3 years ago

5 0

Answer:

200.

Step-by-step explanation:

yw, have a good day!

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Can a line be parallel to a segemnt?

zmey [24]

You can describe lines, rays, and line segments by the way they meet or cross each other. Words Parallel lines are always the same distance apart. They do not meet. Words Lines that meet or cross each other are called intersecting lines. Hope this helps.

6 0

3 years ago

A randomly selected sample of college basketball players has the following heights in inches. See Attached Excel for Data. Compu

Illusion [34]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The confidence interval is $64.86$

Step-by-step explanation:

From the question we are given the following data

The following heights are

66, 65, 67, 62, 62, 65, 61, 70, 66, 66, 71, 63, 69, 65, 71, 66, 66, 69, 68, 62, 65, 67, 65, 71, 65, 70, 62, 62, 63, 64, 67, 67

The sample size is n =32

The confidence level is $k = 95$ % = 0.95

The mean is evaluated as

$\= x = 66+ 65+ 67+ 62+ 62+ 65+ 61+ 70+ 66+ 66+ 71+63+ 69+ 65+ 71+ 66+ 66+ 69+ 68+ 62+ 65+ 67,+\\65+ 71+ 65+ 70+ 62+ 62+ 63+ 64+ 67+ 67 / 32$

=> $\= x = \frac{2108}{32}$

=> $\= x = 65.875$

The standard deviation is evaluated as

$\sigma = \sqrt{ v}$

Now

$v = ( 66-65.875 )^2+(65-65.875)^2+( 67-65.875)^2+ (62-65.875)^2+ (62-65.875)^2+ (65-65.875)^2+( 61-65.875)^2+ (70-65.875)^2+ (66-65.875)^2+ (66-65.875)^2+ (71+63-65.875)^2+ (69-65.875)^2+ (65-65.875)^2+ (71-65.875)^2+( 66-65.875)^2+ (66-65.875)^2+ (69-65.875)^2+ (68-65.875)^2+ (62-65.875)^2+ (65-65.875)^2+ (67-65.875)^2,+\\(65-65.875)^2+ (71-65.875)^2+ (65-65.875)^2+ (70-65.875)^2+( 62-65.875)^2+( 62-65.875)^2+ (63-65.875)^2+ (64-65.875)^2+ (67-65.875)^2+ (67-65.875)^2 / 32$

=> $v= 8.567329$

=> $\sigma = \sqrt{8.567329}$

=> $\sigma = 2.927$

The level of significance is evaluated as

$\alpha = 1 - 0.95$

$\alpha = 0.05$

The degree of freedom is evaluated as

$Df = n- 1 \equiv Df = 32 -1 = 31$

The critical values for the level of significance is obtained from the z -table as

$t_c = t_{\alpha/2 } , Df = t _{0.05/2}, 31 =\pm 1.96$

The confidence interval is evaluated as

$\mu = \= x \pm t_c * \frac{\sigma }{\sqrt{n} }$

substituting values

$\mu =65.875 \pm 1.96* \frac{2.927}{\sqrt{32} }$

$\mu =65.875 \pm 1.01415$

=> $64.86$

4 0

3 years ago

(sinA-cosA+1)/(sinA+cosA-1)=2(1+cosecA)

borishaifa [10]

Answer:

The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

Step-by-step explanation:

Given Trigonometrical function as :

$\frac{sin A - cos A + 1}{sin A + cos A - 1}$ = 2 (1 + cosec A)

Or, $\frac{sin A + ( 1 - cos A)}{sin A - (1 - cos A)}$ = 2 (1 + cosec A)

, Now, rationalizing

$\frac{(sin A + ( 1 - cos A)) \times (sin A + (1 - cosA))}{(sin A - (1 - cos A))\times (sin A + (1 - cos A))}$ = 2 (1 + cosec A)

Or, $\frac{(sin A + (1 - cos A))^{2}}{sin^{2} - (1-cos A)^{2}}$ = 2 ( 1 + $\dfrac{1}{\textrm sinA}$

Or, $\frac{sin^{2}A + (1 - cosA)^{2} + 2 \times sin A \times (1 - cos A)}{sin^{2}A - (1 + cos^{2}A - 2 cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - 1 - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - (sin^{2}A + cos^{2}A) - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$