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3 years ago

Write (8a^3)^ -2/3 in simplest form. All steps are needed!!

Mathematics

1 answer:

allochka39001 [22]3 years ago

6 0

Answer:1/(2a)^2
Steps:
(8a^3)^ -2/3
=1/(8a^3)^ 2/3
=1/(2^3 × a^3)^ 2/3
=1/(2a)^3×2/3
=1/(2a)^2

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A comprehension test was given to students after they had studied text book material either in silence or with the television tu

Natali5045456 [20]

The independent variable is the study environment. This is because that's what's being changed in the experiment to determine something else. The dependent variable is how we're measuring results. Therefore, in this experiment, it's the result of the comprehension test.

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3 years ago

What is the median of the following set of numbers? 15, 6, 7, 11, 2, 10, 15

Alenkasestr [34]

Answer:

First, you will need to arrange the data in an ascending order and the median is the middle value.

If the number of values is an even number, the median will be the average of the two middle numbers.

2, 6, 7, 10, 11, 15, 15

The median in this set is 10.

Step-by-step explanation:

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3 years ago

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3 years ago

A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is current

lapo4ka [179]

Using the z-distribution, we have that:

The hypothesis test is:

$H_0: \mu = 7.4$

$H_1: \mu < 7.4$

The p-value is of 0.0668.

The critical value is $z^{\ast} = -1.28$

b) Since the test statistic is less than the critical value for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

Item a:

At the null hypothesis, it is tested if the mean is of 7.4 minutes, that is:

$H_0: \mu = 7.4$

At the alternative hypothesis, it is tested if the mean is lower than 7.4 minutes, that is:

$H_1: \mu < 7.4$

We have the standard deviation for the population, hence, the z-distribution is used.

The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

$\sigma$ is the standard deviation of the sample.

n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 7.1, \mu = 7.4, \sigma = 1.2, n = 36$ .

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{7.1 - 7.4}{\frac{1.2}{\sqrt{36}}}$

$z = -1.5$

Using a z-distribution calculator, the p-value is of 0.0668.

Also using a calculator, considering a left-tailed test, as we are testing if the mean is less than a value, the critical value with a significance level of 0.1 is of $z^{\ast} = -1.28$ .

Item b:

Since the test statistic is less than the critical value for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

You can learn more about the use of the z-distribution to test an hypothesis at brainly.com/question/16313918

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Answer:

Step-by-step explanation:

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