Question

Use trigonometry to solve the triangle shown. Round all side lengths to one decimal place and

Answer 1

Answer/Step-by-step explanation:

Recall: SOH CAH TOA

✔️Find <A:

Reference angle (θ) = A

Opposite side = 14 cm

Hypotenuse = 20 cm

Apply SOH:

Sin θ = Opp/Hyp

Substitute

Sin A = 14/20

A = $sin^{-1}(\frac{14}{20})$

m<A = 44° (nearest whole number)

✔️Find <C:

Reference angle (θ) = C

Adjacent side = 14 cm

Hypotenuse = 20 cm

Apply CAH:

Cos θ = Adj/Hyp

Substitute

Cos C = 14/20

C = $cos^{-1}(\frac{14}{20})$

m<C = 46° (nearest whole number)

✔️Find AB:

Reference angle (θ) = C = 46°

Opposite side = AB

Hypotenuse = 20 cm

Apply SOH:

Sin θ = Opp/Hyp

Sin 46° = AB/20

20*Sin 46° = AB

AB = 14.4 cm (one decimal place)