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Aleksandr [31]
3 years ago
7

Jeff hiked for 2 hours and traveled 5 miles. If he continues at the same pace, which equation will show the relationship between

the time, t, in hours he hikes to distance, d, in miles? Will the graph be continuous or discrete?

Mathematics
2 answers:
lesya692 [45]3 years ago
5 0

Answer:

d

Step-by-step explanation:

Lady_Fox [76]3 years ago
3 0

Answer: The relationship between distance and time is d=2.5t and the graph is continuous.

Step-by-step explanation:

Since we have given that

Number of hours he hiked = 2 hours

Distance covered = 5 miles

Speed would be

\dfrac{Distance}{Time}\\\\=\dfrac{5}{2}\\\\=2.5\ mph

Let the distance be 'd'.

Let the time be 't'.

so, the relation between distance and time would be

distance=Speed\times time\\\\d=2.5t

The graph  is continuous because it is not based on counts and the points are  connected with a continuous line without any break.

Hence, the relationship between distance and time is d=2.5t and the graph is continuous.

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If you sold 17 units this week out of 153 units in inventory, what percent of your inventory did you sell?
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11.1%

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3 years ago
With a little care, you can find the median and the quartiles from the histogram. what are these numbers? you can also find the
coldgirl [10]

Complete Question

The histogram from this question is shown on the first uploaded image

Answer:

The first quartile is  1st Q = 19^{th} girl (subject ) = 1 \serving\ of\ fruit\ per\ day

The median is   Median  = 38 ^{th} \ girl (subject) =  2 \serving\ of\ fruit\ per\ day

The third quartile  is 3rd Q =  56^{th} \  girl (subject) = 4 \serving\ of\ fruit\ per\ day  

The  mean is  \= x = 2.62

Step-by-step explanation:

From the question we are told that

   The total  number of girls is n =  74

Generally the median is mathematically represented as

       Median  =  \frac{\frac{n}{2}  +[ \frac{n}{2} + 1]  }{2}

So

          Median  =  \frac{\frac{74}{2}  +[ \frac{74}{2} + 1]  }{2}

=>         Median  =  \frac{37  +38 }{2}

=>         Median  =37.5 \  girl    

From the histogram 37.5 \approx 38^{th} \ girl fall under 2 fruits per day

Generally the first quartile is mathematically represented as

      1st \ Q =  \frac{\frac{n}{4} + [\frac{n}{4} + 1]  }{2}

=>    1st \ Q =  \frac{\frac{74}{4} + [\frac{74}{4} + 1]  }{2}

=>     1st \ Q = 19 \  girl

From the histogram 19^{th}girl fall under 1 fruit per day

 Generally the third quartile is mathematically represented as

     3rd\  Q =  \frac{\frac{n}{2}  + n }{2}

=>    3rd\  Q =  \frac{\frac{74}{2}  + 74 }{2}

=>    3rd\  Q =  55.5

From the histogram 55.5 \approx 56^{th} \ girl fall under 4 fruits per day

Generally from the histogram table the frequency  [number of subjects (girls) ]  and the servings of fruit per day can be represented as

                                                                                                               Total

x(servings per day )        0     1     2     3     4     5    6     7      8    

f (number of subjects )   15    11   15     11    8     5    3     3      3    \sum f  =  74

xf                                       0    11    30   33   32  25   18   21     24    \sum xf =  194

Generally the mean is mathematically represented as

      \= x = \frac{1}{ \sum f}  * [\sum xf]

=>     \= x = \frac{1}{ 74}  *194

=>      \= x = 2.62

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Gala2k [10]
<span>Saul works at the local car dealership.
=> He makes 2% commission on all sales.
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3 years ago
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