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kaheart [24]
4 years ago
13

Zekia divides 6 cups of fruit juice equally among 8 friends. 2 of her friends don't drink the juice. How much is leftover? Thank

s for helping!! I'm looking for Brainliest answer!!!
Mathematics
2 answers:
maxonik [38]4 years ago
7 0
First Step - Divide 6 by 8 to find how much juice each friend was given (0.75)
Second Step - Two friends didn't drink so add 0.75 + 0.75 to find out how much is left (1.5)

There is 1 1/2 cups of juice left

Hope I helped! :D
BlackZzzverrR [31]4 years ago
5 0
6 = 8f - 2f
6 = 6f
f = 1

there is no leftover as each friend get 1 cup
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Step-by-step explanation:

Answer: 91.7 = .6 (92) + .3 (90) + .1(95

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3 years ago
Which points are on the the graph equation -3x+6y+5=-7
algol [13]
-3x + 6y + 5 = -7
<u>                -5    -5</u>
      -3x + 6y = -12
-3x + 3x + 6y = -12 + 3x
               <u>6y</u> = <u>-12 + 3x</u>
                6           6
                 y = -2 + 1/2x
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6 0
4 years ago
AaBbCc x AaBbCc (use for all 3 questions) 1. What is the probability that this individual will: AABBcc 2. What is the probabilit
tankabanditka [31]

Answer: 1. P = 1/64

             2. P = 1/32

             3. P = 1/8

Step-by-step explanation:

In genetics, an ofspring inherits one copy of an allele of each parent, which can be described in the tables below called Punnett Square:

For crossing Aa x Aa:

       A      a

A    AA   Aa

a    Aa    aa

For crossing Bb x Bb:

        B      b

B     BB    Bb

b     Bb    bb

For crossing Cc x Cc:

       C      c

C    CC    Cc

c     Cc     cc

We can separate them because they are assorted independently.

For offspring with <u>genotype</u> <u>AABBcc</u>, probability will be:

P(AA) = 1/4

P(BB) = 1/4

P(cc) = 1/4

As all three probabilities has to happen at the same time, it is a "E" rule:

P(AABBcc) = (\frac{1}{4}) (\frac{1}{4}) (\frac{1}{4})

P(AABBcc) = 1/64

Probability for the individual to be AABBcc is 1/64 or 1.56%.

<u>Genotype</u> <u>AaBBcc</u>:

P(Aa) = 2/4 = 1/2

P(BB) = 1/4

P(cc) = 1/4

P(AaBBcc) = (\frac{1}{2}) (\frac{1}{4}) (\frac{1}{4})

P(AaBBcc) = 1/32

Probability for the individual to be AaBBcc is 1/32 or 3.12%

<u>Genotype</u> <u>AaBbCc</u>:

P(Aa) = 1/2

P(Bb) = 1/2

P(Cc) = 1/2

P(AaBbCc) = (\frac{1}{2}) (\frac{1}{2}) (\frac{1}{2})

P(AaBbCc) = 1/8

Probability for the individual to be AaBbCc is 1/8 or 12.5%.

4 0
3 years ago
How do I solve this problem?
geniusboy [140]

Answer:

i think is 7/12

because if 4/7 chose pasta,1/5 chose pizza then we add 7+5=12 then we sudstract 12-4-1 = 7.

hope that helps

4 0
2 years ago
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