The answer to your question is A. 40%
Answer:
Answer: 91.7 = .6 (92) + .3 (90) + .1(95
Step-by-step explanation:
Answer: 91.7 = .6 (92) + .3 (90) + .1(95
Main Heading: Time Series
Key words: weighted moving average
-3x + 6y + 5 = -7
<u> -5 -5</u>
-3x + 6y = -12
-3x + 3x + 6y = -12 + 3x
<u>6y</u> = <u>-12 + 3x</u>
6 6
y = -2 + 1/2x
-3x + 6(-2 + 1/2x) = -12
-3x - 12 + 3x = -12
-3 + 3x - 12 = -12
0x - 12 = -12
<u> +12 +12</u>
<u>0x</u> = <u>0</u>
0 0
x = 0
-3(0) + 6y = -12
0 + 6y = -12
<u>+0 +0</u>
<u>6y</u> = <u>-12</u>
6 6
y = -2
(x, y) = (0, -2)
Answer: 1. P = 1/64
2. P = 1/32
3. P = 1/8
Step-by-step explanation:
In genetics, an ofspring inherits one copy of an allele of each parent, which can be described in the tables below called Punnett Square:
For crossing Aa x Aa:
A a
A AA Aa
a Aa aa
For crossing Bb x Bb:
B b
B BB Bb
b Bb bb
For crossing Cc x Cc:
C c
C CC Cc
c Cc cc
We can separate them because they are assorted independently.
For offspring with <u>genotype</u> <u>AABBcc</u>, probability will be:
P(AA) = 1/4
P(BB) = 1/4
P(cc) = 1/4
As all three probabilities has to happen at the same time, it is a "E" rule:
P(AABBcc) = 
P(AABBcc) = 1/64
Probability for the individual to be AABBcc is 1/64 or 1.56%.
<u>Genotype</u> <u>AaBBcc</u>:
P(Aa) = 2/4 = 1/2
P(BB) = 1/4
P(cc) = 1/4
P(AaBBcc) = 
P(AaBBcc) = 1/32
Probability for the individual to be AaBBcc is 1/32 or 3.12%
<u>Genotype</u> <u>AaBbCc</u>:
P(Aa) = 1/2
P(Bb) = 1/2
P(Cc) = 1/2
P(AaBbCc) = 
P(AaBbCc) = 1/8
Probability for the individual to be AaBbCc is 1/8 or 12.5%.
Answer:
i think is 7/12
because if 4/7 chose pasta,1/5 chose pizza then we add 7+5=12 then we sudstract 12-4-1 = 7.
hope that helps