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EastWind [94]
2 years ago
10

A contest is being held at a school fair for seventh-grade

Mathematics
2 answers:
pshichka [43]2 years ago
6 0

Answer:

3/7

Step-by-step explanation:

ofc theres 70 students all together, the 3 represents 30 eighth-graders and the 7 is the 70 students all together, 3+4=7 blah blah blah :)

DerKrebs [107]2 years ago
4 0
The answer is c.. hope this helps
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Problem 1

The Blue Jays had the most passing yards. Circle the "passing" column, which is column 1. Then look for the largest value in this column. This largest value is 108 which belongs to the Blue Jays.

--------------------------------------------------------------

Problem 2

The answer is choice B. To get this answer, you multiply every value inside the matrix by -5
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3 years ago
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Mica bought a new smart phone for $258.13. That was the price after his 18.25% discount. What was the original price of the phon
julia-pushkina [17]

The original price of phone is $ 315.76

<em><u>Solution:</u></em>

Given that Mica bought a new smart phone for $ 258.13.

That was the price after his 18.25% discount

<em><u>To find: original price of phone</u></em>

From given question,

price after discount = $ 258.13

discount = 18.25 %

Let "x" be the original price of phone

price after discount = original price - discount

258.13 = x - 18.25 \% \text{ of } x

258.13 = x - \frac{18.25}{100}x

258.13 = x(1 - \frac{18.25}{100})

258.13 = x(1 - 0.1825)\\\\258.13 = x( 0.8175)\\\\x = \frac{258.13}{0.8175}\\\\x = 315.76

Thus original price of phone is $ 315.76

4 0
3 years ago
A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

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2 years ago
9.a )Explain why plane JKL is not an appropriate
VLD [36.1K]

Answer:

I will attach the missing drawing with the answer.

9.b)

Plane JKM

Plane JLM

Plane KLM

Step-by-step explanation:

The drawing for this question is missing. I will attach it with the answer.

9.a) Plane JKL is not an appropriate name for the plane because all of three points lie in the same line.

Through a line pass infinite planes. The plane JKL doesn't define a unique plane. That's why plane JKL isn't an appropriate name for the plane.

9.b) We can name the plane using three points that don't lie in the same line.

Three possible names for the plane are :

Plane JKM

Plane JLM

Plane KLM

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Answer: Lunch:$16 Coffee: $4 Julie had $12 left.

Step-by-step explanation:

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