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andriy [413]
3 years ago
14

Pls help and show workings due ASAP

Mathematics
1 answer:
Fed [463]3 years ago
7 0

Answer:

goodluck

Step-by-step explanation:

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In the following diagram lines m are n parallel the measures of AEB, BAE and CED are shown what is the measure of EBF
guapka [62]

Answer:

∠ EBF = 98°

Step-by-step explanation:

(3x - 15) and (2x + 10) are vertically opposite angles and are congruent, then

3x - 15 = 2x + 10 ( subtract 2x from both sides )

x - 15 = 10 ( add 15 to both sides )

x = 25

3x - 15 = 3(25) - 15 = 75 - 15 = 60°

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ EBF is an exterior angle of the triangle , then

∠ EBF = 60° + 38° = 98°

8 0
3 years ago
2x+3x Equals? Please help!!
satela [25.4K]

Answer:

the answer is 5x

Step-by-step explanation:

8 0
3 years ago
FREEEEEEEEEEEEEEEEEEEEEEEE POINTS!!!!!!!!!!!!!
muminat
Bless ur kind soul :o
4 0
3 years ago
Suppose you hit a fly ball with an initial upward velocity of 20 feet per second. Which of the following equations would be a re
baherus [9]
A=g≈-32

v=⌠a dt  since a≈-32

v=-32t+C, where C is the initial velocity, which we are told is 20 ft/s

v=-32t+20

h=⌠v dt

h=-32t^2/2+20t+C, where C is the initial height, so what is a reasonable initial height?  How about 3 ft since we are swinging a bat around maybe our waist level... maybe :P

h=-16t^2+20t+3

Your choices may have made a different assumption about the initial height of course but you did not show your choices, but certainly it will be:

h(t)=-16t^2+20t+hi, where hi is the initial height in feet.

This of course ignores air resistance and flight dynamics of a spinning ball with seams, which will make a significant difference in real life :)
3 0
3 years ago
Read 2 more answers
What is the equation of the quadratic graph with a focus of (4, −3) and a directrix of y = −6?
Artyom0805 [142]

Answer:

y=\frac{1}{6} (x-4)-\frac{9}{2}

Step-by-step explanation:

∵ The quadratic equation form is :

y = [1/2(b - k)] (x - a)² + (b + k)/2

Where (a , b) is the focus and directrix y = k

∵ The focus is (4 , -3) and directix is y = -6

∵ y=\frac{1}{2(-3-(-6))} (x-4)^{2}+\frac{(-3)+(-6)}{2}

∴ y=\frac{1}{6} (x - 4)^{2}+\frac{-9}{2}

∴ y=\frac{1}{6} (x-4)-\frac{9}{2}

another way:

Assume that (x , y) is the general point on the parabola

∵ The distance between the directrix and (x , y) = the distance between the focus and (x , y)

By using the distance rule:

∵ (y - -6)² = (x - 4)² + (y - -3)² ⇒ (y + 6)² = (x - 4)² + (y + 3)

∴ y² + 12y + 36 = (x - 4)² + y² + 6y + 9

∴ 12y - 6y = (x - 4)² + 9 - 36

∴ 6y = (x - 4)² - 27 ⇒ ÷ 6

∴ y = 1/6 (x - 4)² - 9/2

4 0
3 years ago
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