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hoa [83]
3 years ago
13

A relay team of 4 people runs 3 miles.If each person runs the same distance,How many miles does each person run?

Mathematics
2 answers:
Len [333]3 years ago
6 0
Well first you have to divide 3 by 4, which is 0.75 or 3/4
Naddika [18.5K]3 years ago
6 0
5,280*3=15,840. 15,840/4=3,960. Each person runs 3,960 feet.
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Which operation would isolate the variable in this equation?
Blababa [14]

Answer:

D. Divide both sides by - 8

Step-by-step explanation:

-8x = 312

x = 312/(-8)

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5 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
ILL MARK BRAINILEST !! 80 POINTS
mixas84 [53]

\\ \rm\rightarrowtail y=x^2-10x+16

\\ \rm\rightarrowtail y=x^2-10x+16+9-9

\\ \rm\rightarrowtail y=x^2-10x+25-9

\\ \rm\rightarrowtail y=(x-5)^2-9

Vertex form

  • y=a(x-h)^2+k

So

vertex:-

  • (h,k)=(5,-9)
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If tan y = 3 over y and cos x = y over z what is the value of sin x??
LekaFEV [45]
The answer should be C
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