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AURORKA [14]
3 years ago
6

Find the distance between point A and point B. A) 5 B) 6 C) 8 D) 9

Mathematics
2 answers:
Sophie [7]3 years ago
8 0

Answer:

Need more info

Contact [7]3 years ago
6 0
Post a picture of the graph
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The distance from Ari’s house, A, to Ben’s house, B, is equal to the distance from Ari’s house to Cal’s house, C. One day the bo
tresset_1 [31]

Answer:

they walked the same distance

Step-by-step explanation:

if you add cal's expression up which is 2(2+1)+(-4) you would have to use distributive property which means you would have to times 2 by 2 which is 4 and then  times 2  by 1 and get two and then add them together and  get 2 and if you do the same thing with Ari's expression you get  2.

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3 years ago
Why was the year 1492 so important to Spanish history?
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The year 1492 is an important date for Spain as a whole, but especially in the small, luscious city of Granada. ... As a result, these conquests brought both the Spanish language and culture to Latin America and the Caribbean as well as pumped economic wealth into Spain.

4 0
3 years ago
Find the perimeter of ΔABC and how you got it.
coldgirl [10]

Answer:

\fbox{Perimeter of ∆ABC = 54 units}

Step-by-step explanation:

Given:

➳ AC || RP

➳ AC = 18 units

➳ AR = 14 units

➳ RB = 7 units

➳ CP = 10 units

To find:

perimeter of triangle ABC =?

Solution:

in ∆ABC and ∆RBP

since we know AC || RP,

then ∠ACP = ∠RPB

and ∠CAB = ∠PRB (Property of parallel lines)

and ∠B is a common angle in both traingles,

hence ∆ABC ~ ∆RBP from AAA property!

now,

using the properties of similar triangle,

\frac{AR   }{RB}  =  \frac{CP}{PB} \\   \\  \frac{14}{7}  =  \frac{10}{PB}  \\  \\ X =  \frac{10}{2}  \\   \\ \fbox{PB = 5} \\  \\  \\

To find perimeter of ∆ABC, add all the components.

Perimeter of ∆ABC = AR + RB + BP +PC + CA

Perimeter of ∆ABC= 14 + 7 +5 +10 + 18 units

\fbox{Perimeter of ∆ABC = 54 units}

<em><u>Thanks for joining brainly community! </u></em>

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3 years ago
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How would I solve this, converting the left side to a square root? -16 = r^3
ZanzabumX [31]

-16=r^3\implies \sqrt[3]{-16}=\sqrt[3]{r^3}\implies \sqrt[3]{-16}=r\implies \sqrt[3]{-2^4}=r \\\\\\ \sqrt[3]{(-2)^3\cdot 2^1}=r\implies -2\sqrt[3]{2^1}=r\implies -2\sqrt[3]{2}=r

7 0
2 years ago
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