Answer:
115<40+15x
i believe this is right. 115 is what he has and what he spends has to be less than that and x is how many lines so solve for x to find how many lines he can have
Answer:
To find the slope of this line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y. But the slope of the lines will be the same.
Answer:
The GCF of 27 and 45 is 9.
Step-by-step explanation:
Factors of 27: 1, 3, 9
Factors of 45: 1, 3, 5, 9, 15
The biggest number in both is 9 so the GCF is 9
<span>2.8 x 10^6 N
We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that:
F * 35m = 9.8 x 10^7 kg*m^2/s^2
Solving for F, gives
F * 35m = 9.8 x 10^7 kg*m^2/s^2
F = 9.8 x 10^7 kg*m^2/s^2 / 35m
F = 2.8 x 10^6 kg*m/s^2
F = 2.8 x 10^6 N
So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>
If logs are subtracting, you can divide the brackets and if they are adding, you can multiply the brackets. Also, if the number comes before the log, it's can be Taken up as a power. so you end up with:
6log(25-x^2) - [log(5+X) + log(5-X)]
= log(25-x^2) - log(25-x^2)
= log (25-x^2/25-x^2)
= log(1)
log
