When it comes to laplace equations, there are transformation equations to follow. Generally, when you want to transform a laplace equation, you change the equation from f(t) to F(s). If you do the reverse, it is called the reverse laplace equation.
Based on the given, the useful transformation equation is shown in the attached picture.
When the term is s^2, that must mean that the equation is 1!/s^(1+1) to yield 1/s^2. This means that n=1. Taking the reciprocal s^2 must be equal to 1/t. Thus, for the first term, -11s^2 is equal to -11/t. For the second term, n must be equal to 6 so that 6!/s^(6+1) would yield 720/s^7. Thus, 720s^7 is equal to 1/t^6.
Hence, the transformed equation is
-11/t - 1/t^6
Answer:
3/10 ÷ 7/9 = 3/10 • 9/7
Step-by-step explanation:
KCF for division.
7/9= 9/7
÷=x
The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.
<h3>What is the area of the circle and the square?</h3>
The area of the circle is
Ac = πr² = πd²/4 sq. units
Where r is the radius and d is the diameter of the circle.
The area of the square is given by
As = s² sq. units
Where s is the length of the side of a square.
<h3>Calculation:</h3>
It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.
So,
The area of pizza is
Ap = Ac = πd²/4 sq. units
= π(10)²/4
= 25π
= 78.54 sq. in
Then, the area of the square box with the length same as the diameter of the pizza is,
As = d²
= 10²
= 100 sq. in
Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.
Learn more about the area of a circle here:
brainly.com/question/15673093
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Anwser is 10cm bc you multiply 10amd 3 then divided it
Just squish the two equations into one equation and idk im just typing this because i apparently need a twenty character long answer