Answer:
As p-value = 0.0.68 > 0.05 the null hypothesis could not be rejected
Step-by-step explanation:
The computation of the p-value is shown below:
Given that
Average life = = 88.5
Standard deviation = = 9
Sample = n = 80
Based on the above information
Null and alternative hypothesis is
Now for the level of significance = 0.05 and the critical value for a right talied test is
Now the test statistic is
= 1.491
Now it is observed that
Z = 1.49≤z_ c = 1.64
So by this the null hypothesis could not be rejected
So,
P -value = 1 - P(z<1.491)
P-value = 0.068
As p-value = 0.0.68 > 0.05 the null hypothesis could not be rejected