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2 years ago

Which linear function represents the line given by the point-slope equation y – 8 =1/2 (x – 4)?

Mathematics

2 answers:

elixir [45]2 years ago

7 0

Answer: The correct option is B.

Explanation:

The given equation is,

$(y-8)=\frac{1}{2} (x-4)$

We need to simplify the above equation and separate the variable y.

Multiply both sides by 2.

$2(y-8)=x-4$

$2y-16=x-4$

Add 16 both sides.

$2y=x+12$

Divide both sides by 2.

$y=\frac{1}{2}x+\frac{1}{2}(12)$

$y=\frac{1}{2}x+6$

Therefore option B is correct.

Setler79 [48]2 years ago

5 0

B is the correct option
ditribute first on the right side
then add 8 to the right side and that will make y by itself

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The area of this square

ANEK [815]

It appears as if 12cm is half the length of the side so we can assume that the total length of one side is 24cm.

The area of a square is given by the equation $A=s^{2}$ where s is the length of the side.

$A=24^{2}$

A=576

The area of this square is 576cm2.

Hope this helps!

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2 years ago

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seraphim [82]

Answer:

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3 years ago

Read 2 more answers

Will mark brainliest and rate 5/5

Levart [38]

Answer: Usually the formula for the volume of a prism is V=b(h)—> In words, Volume equals base times height. This means the height 10 would replace h. —> V=b(10). Next we want to find the B in the forumla. If you notice the question says that the base is 24 square centimeters. So our new formula is V=24(10). So option C, V=24x10 is the correct answer.

8 0

2 years ago

Ritu is travelling by a car at a speed of

faltersainse [42]

Answer:

40 min is the answer

Step-by-step explanation:

To solve this we need to convert all the units into SI units

for ritu,

speed= 90km/hr

= 90 × 1km/ 1hour

= 90×1000/3600 m/s

= 25m/s

distance = 120×1000m

time = distance/ speed

= 120000/25

= 4800sec

= 4800/60min

= 80 min

for garima,

distance =120×1000m

speed = 60km/hr

= 60×1000/3600 m/s

=100/6 m/

time = 120000/(100÷6)

= 7200sec

= 7200÷60 min

= 120 min

time difference is 120-80 = 40 min

4 0

2 years ago

Suppose the object moving is Dave, who hasamassofmo =66kgatrest. Whatis Daveâs mass at 90% of the speed of light? At 99% of the

nignag [31]

Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

$m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}$

Where :

m = mass of the oebjct in motion

$m_o$ = mass of the object when at rest

v = velocity of a moving object

c = speed of the light = $3\times 0^8 m/s$

We have :

1) Mass of the Dave = $m_o=66 kg$

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}$

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}$

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}$

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = $m_o=66 kg$

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

$500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}$

$v=2.973\times 10^8 m/s$

Dave should be moving at speed of $2.973\times 10^8 m/s$ .

4 0

3 years ago