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svetoff [14.1K]
3 years ago
7

Which linear function represents the line given by the point-slope equation y – 8 =1/2 (x – 4)?

Mathematics
2 answers:
elixir [45]3 years ago
7 0

Answer: The correct option is B.

Explanation:

The given equation is,

(y-8)=\frac{1}{2} (x-4)

We need to simplify the above equation and separate the variable y.

Multiply both sides by 2.

2(y-8)=x-4

2y-16=x-4

Add 16 both sides.

2y=x+12

Divide both sides by 2.

y=\frac{1}{2}x+\frac{1}{2}(12)

y=\frac{1}{2}x+6

Therefore option B is correct.

Setler79 [48]3 years ago
5 0
B is the correct option
ditribute first on the right side
then add 8 to the right side and that will make y by itself
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0.62% probability that a ski resort averages more than 3,000 customers per weekday over the course of four weekdays

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 2000, \sigma = 800, n = 4, s = \frac{800}{\sqrt{4}} = 400

Trobability a ski resort averages more than 3,000 customers per weekday over the course of four weekdays.

This is 1 subtracted by the pvalue of Z when X = 3000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

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Z = 2.5

Z = 2.5 has a pvalue of 0.9938

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0.62% probability that a ski resort averages more than 3,000 customers per weekday over the course of four weekdays

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3 years ago
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