We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:
Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:
5^2 = 3^2 + x^2
x = 4
The radius is 4 + 1 cm = 5 cm
So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2
A = 25pi cm^2
To solve for the area of the shaded region:
Ashaded = Acircle - Atriangles
we need to solve for the area of the triangles:
A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2
Atriangles = 2 * 15
Atriangles = 30 cm^2
Ashaded = 25pi - 30
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Answer:
82
Step-by-step explanation:
Answer:
Step-by-step explanation:
The equation of a direct variation is generally written as:
Where m is the slope of the equation of the direct variation line.
We want a direct variation equation that contains (6,-2).
We substitute the x=6 and y=-2 to find m.
Divide both sides by 6.
The required equation is
Answer:
C
Step-by-step explanation: