The answer to this question is:
A circle is growing so that the radius is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.?
✔️I assume here the linear scale is changing at the rato of 5cm/min
✔️dR/dt=5(cm/min) (R - is the radius.... yrs, of the circle (not the side)
✔️The rate of area change would be d(pi*R^2)/dt=2pi*R*dR/dt.
✔️At the instant when R=20cm,this rate would be,
✔️2pi*20*5(cm^2/min)=200pi (cm^2/min) or, almost, 628 (cm^2/min)
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5 times n=17 because you have to use algebra
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
Remember that in a quotient, the denominator cannot be equal to zero
so
The value of x cannot be equal to x=-2
Simplify the expression
Using a graphing tool
The roots of the quadratic equation in the numerator are
x=-2 and x=1
so
Simplify the denominator
substitute in the original expression
Simplify
Is the equation of a line
The y-intercept is the point (0,-3) (value of the function when x is equal to zero)
The x-intercept is the point (1,0) (value of x when the value of the function is equal to zero)
Graph the line, but remember that the value of x cannot be equal to -2
The graph in the attached figure
Answer:
The amount depositied is less than or equal to the amount of money in his wallet.
Step-by-step explanation:
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