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shepuryov [24]
3 years ago
15

Find S5 for the sequence 3, 13, 23, 33, 43, 53, 63, 73.

Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0
The sequence is
                          3 , 13 , 23 , 33 , 43 , 53 , 63 , 73
S5 ⇒ The sum of the first 5 terms of the sequence
∴ S5 = 3 +13 + 23 + 33 + 43 = 115

So, the answer is option (B)
=========================================================
    Another solution:
----------------------------
It is observed that the first number = 3
And each number increased by 10 from its previous number
So, the sequence is an arithmetic series.
let       a ⇒ is the first term of an arithmetic sequence .
and    d  ⇒ is the difference between terms of the arithmetic sequence .
So     Sn ⇒ is the sum of n terms in the arithmetic sequence .

         Sn = (n/2)( 2a + d (n-1) )

for a = 3 , d = 10 , n = 5

         Sn = (5/2)( 2*3 + 10 (5 -1) ) = 115 ⇒⇒⇒⇒⇒ option (B)










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<h3>:- Solution</h3>

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3 0
3 years ago
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lawyer [7]

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Step-by-step explanation:

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<u />

============================================================

Then the formula will be :

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8 0
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uppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.5
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Step-by-step explanation:

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x = 3.24

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P(x \le 3.24) = 0.97725

6 0
3 years ago
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