Two selectively permeable sacs A and B were submerged in a 45% glucose solution that was contained in a beaker. Sac A contained

Question

3 years ago

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Two selectively permeable sacs A and B were submerged in a 45% glucose solution that was contained in a beaker. Sac A contained

a 15% glucose solution and Sac contained a 15% sucrose solution. In which direction did net movement of water molecules occur? a. Only from Sac A to the beaker b. Only from Sac B to the beaker c. From the beaker to both sacs d. From both sacs to the beaker

Biology

1 answer:

Vesnalui [34] · Answer 1 · 2022-03-24T11:59:45+03:00

Answer:

Option a. Only from Sac A to the beaker is correct.

Explanation:

As beaker contains glucose which is a monosaccharide and Sac A also have glucose in it, So, therefore glucose from sac A will move into beaker through the process of OSMOSIS.

Sac A (15% glucose) is less concentrated as compared to beaker (45% glucose) therefore this phenomenon will occur. (See attached image for more detailed and graphical explanation)