Answer:
There's no direct variation
Step-by-step explanation:
Required
Determine if there's a direct variation between the number and its position
I'll start by giving an illustration of how the triangle is represented using stars (*)
*
**
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Represent the line number with y and it's position with x
On line 1:
y = 1, x = 1
On line 2:
y = 2, x = 3
On line 3:
y = 3, x = 6
On line 4:
y = 4, x = 10
On line 5:
y = 5, x = 15
Note that, x is gotten by calculating the accumulated number of stars while y is the line number.
Direct variation is represented by
y = kx
Or
kx = y
Where k is the constant of variation
For line 1:
Substitute 1 for y and 1 for x
k * 1 = 1
k = 1
For line 2:
Substitute 2 for y and 3 for x
k * 3 = 2
Divide through by 3
k = ⅔
Note that the values of k in both computations differ.
This implies that there's no direct variation and there's no need to check further.
3/4 can be sliced from three pieces
Answer:
Step-by-step explanation:
perp. -5
y + 7 = -5(x - 4)
y + 7 = -5x + 20
y = -5x + 13
First, you would multiply $210 by 20%
This is done by converting 20% to a decimal, .2
So, 210 • .2 = 42
Then to find the sale price, you would subtract that 42 that you just got from 210,
and you get $168 as the final sale price.
<h3>Answer:</h3>
(x, y) ≈ (1.49021612010, 1.22074408461)
<h3>Explanation:</h3>
This is best solved graphically or by some other machine method. The approximate solution (x=1.49, y=1.221) can be iterated by any of several approaches to refine the values to the ones given above. The values above were obtained using Newton's method iteration.
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Setting the y-values equal and squaring both sides of the equation gives ...
... √x = x² -1
... x = (x² -1)² = x⁴ -2x² +1 . . . . . square both sides
... x⁴ -2x² -x +1 = 0 . . . . . polynomial equation in standard form.
By Descarte's rule of signs, we know there are two positive real roots to this equation. From the graph, we know the other two roots are complex. The second positive real root is extraneous, corresponding to the negative branch of the square root function.
