Please help me need ASAP
1 answer:
You might be interested in
Answer:
is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Step-by-step explanation:
Given the function
As the highest power of the x-variable is 3 with the leading coefficients of 1.
- So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.
solving to get the zeros
∵
as
so
Using the zero factor principle
if
Therefore, the zeros of the function are:
is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Therefore, the last option is true.
Use the chain rule.
Let u = 25sin²(x), such that dy/dx = dy/du · du/dx
Let u = 25sin²(x), such that dy/dx = dy/du · du/dx