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Anestetic [448]
3 years ago
13

Julian walked 6/10 of a mile to his friends house and another 35/100 mile to the store. He walked 1/4 of a mile back home. Julia

n's sister said he walked 1/5 mile. Do you agreed. Why or why not
Mathematics
1 answer:
AveGali [126]3 years ago
3 0

The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked 1\frac{1}{5} \text{ or } \frac{6}{5} miles.

<u>Solution:</u>  

Given that,

  • Julian walked 6/10 of a mile to his friends house
  • Another 35/100 mile to the store
  • He walked 1/4 of a mile back home

To find total distance walked by Julian we have to add the above stated values. That is, \frac{6}{10} +\frac{35}{100} +\frac{1}{4}

Factors of 10 = 5\times2

Factors of 100 = 5\times2\times5\times2

Factors of 4 = 2\times2

Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,

\frac{6\times10}{10\times10} +\frac{35\times1}{100\times1} +\frac{1\times25}{4\times1}\rightarrow\frac{60+35+25}{100}\rightarrow\frac{120}{100}

\Rightarrow\frac{120}{100}\rightarrow\frac{6}{5}

Which can also be written as 1\frac{1}{5}.

So, from the above calculation it can be said that Julian walked 1\frac{1}{5} \text{ miles }.

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Mike and his friends bought cheese wafers for $2 per packet and chocolate wafers for $1 per packet at a carnival. They spent a t
trapecia [35]
A. 2x+y=25; x+y=20
x represents cheese wafers and y represents chocolate wafers.

B. I will choose elimination since there is y and y. I can multiply one equation by -1 to get y and -y, which cancels out.
2x+y=25
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4 0
3 years ago
What is the factorization of 729x15 1000? (9x5 10)(81x10 – 90x5 100) (9x5 10)(81x5 – 90x10 100) (9x3 10)(81x6 – 90x6 100) (9x3 1
Rudiy27

The factors of the equation are \rm (9x^4+10)(81x^{10} -90x^5 + 100).

Given

Equation; \rm  729x^{15 }+ 1000.

<h3>What is the Factor Theorem?</h3>

The Factor Theorem states that a polynomial function with roots  is given by:

\rm a(x-x_1)(x-x_2)......

Where a is the leading coefficient.

The factors of the equation are;

\rm (9x^5 + 10)(81x^{10} -90x^5 + 100)\\\\ 729x^{15}-810x^{10}+900x^5+810x^{10}-900x^5+1000\\\\9x^5(81x^{10} -90x^5 + 100)+10(81x^{10} -90x^5 + 100)\\\\ (9x^4+10)(81x^{10} -90x^5 + 100)

Hence, the factors of the equation are \rm (9x^4+10)(81x^{10} -90x^5 + 100).

To know more about factors click the link given below.

brainly.com/question/195124

4 0
3 years ago
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