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zloy xaker [14]
3 years ago
8

you have an initial amount of 55$ in a savings account and you deposit an equal amount into your account each week. After 6 week

s the account holds 133$. Write an equation that represents the amount y (in dollars) of money in the account after x weeks.
Mathematics
1 answer:
sveticcg [70]3 years ago
3 0
55+added=133
added=amount addeed per week times 6=6x

55+6x=133
minus 55 both sides
6x=78
divide both sides by 6
x=13

add 13 per week

y=13x+55
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The function f(x) = { x + 1 is used to complete this Which statements are true of the given function? Check all that apply. tabl
Dmitry [639]

Answer:

Options (1) and (5)

Step-by-step explanation:

Expression that defines the function is,

f(x)=\frac{1}{2}x+\frac{3}{2}

Option 1

f(-\frac{1}{2})=\frac{1}{2}(-\frac{1}{2})+\frac{3}{2}

          =-\frac{1}{4}+\frac{3}{2}

          =-\frac{1}{4}+1+\frac{1}{2}

          =1+\frac{1}{4}

          =1\frac{1}{4}

So, f(-\frac{1}{2} )=-2 is false.

Option 2

f(0) = \frac{1}{2}(0)+\frac{3}{2}

     = \frac{3}{2}

True.

Option 3

f(1) = \frac{1}{2}(1)+\frac{3}{2}

    = \frac{3+1}{2}

    = 2

Therefore, f(1) = -1 is false.

Option 4

f(2)=\frac{1}{2}(2)+\frac{3}{2}

       =1+1+\frac{1}{2}

       =2\frac{1}{2}

Therefore, f(2) = 1 is false.

Option 5

f(4) =\frac{1}{2}(4)+\frac{3}{2}

     =2+\frac{3}{2}

     =\frac{4+3}{2}

     =\frac{7}{2}

True.

Options (1) and (5) are the correct options.

5 0
3 years ago
1.The entry tickets at a community fair cost $5 for children and $10 for adults. On a certain day 1000 people entered in the fai
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Answer:

568 ADULTS

284 CHILDREN

Step-by-step explanation:

5C+10A=7100

A=2C

5C +10(2C)=7100

5C+20C=7100

25C=7100

C=284

A=2C

A=568

BRAINLIEST???

8 0
2 years ago
In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i
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Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,


was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

\bf \displaystyle \int -32\cdot dt\implies -32t+C
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\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
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-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
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\textit{now to get the positional s(t)}
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\displaystyle \int -32t\cdot dt\implies -16t^2+C
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-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}

when will it reach the ground level? let's set s(t) = 0

\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
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part B)  check the picture below

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2 years ago
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liraira [26]


38

explanation:
133 divided by 3.5
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3 years ago
What is the solution of 10=|7-3x|
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10=|7-3x| \\ 7-3x=10 \vee 7-3x=-10\\ 3x=-3 \vee 3x=17\\ x=-1 \vee x=\dfrac{17}{3}

5 0
2 years ago
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