<u /><u />5.28 dollars per pound multiplied by 3.25 pounds is a total of 3.25*5.28=$17.16.
Length of the bottom of the triangle = x
another side =10+2(x)
last side=6x
the equation is 6^2x10
<h2>Answer:</h2>
<u>1/2 is equal to 0.5, so </u><u>-1/2 is -0.5</u><u>.</u>
If you divide -1 by 2, you get -0.5.
Answer:
The minimum score needed to be considered for admission to Stanfords graduate school is 328.48.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 303, \sigma = 13](https://tex.z-dn.net/?f=%5Cmu%20%3D%20303%2C%20%5Csigma%20%3D%2013)
What is the minimum score needed to be considered for admission to Stanfords graduate school?
Top 2.5%.
So X when Z has a pvalue of 1-0.025 = 0.975. So X when Z = 1.96
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![1.96 = \frac{X - 303}{13}](https://tex.z-dn.net/?f=1.96%20%3D%20%5Cfrac%7BX%20-%20303%7D%7B13%7D)
![X - 303 = 13*1.96](https://tex.z-dn.net/?f=X%20-%20303%20%3D%2013%2A1.96)
![X = 328.48](https://tex.z-dn.net/?f=X%20%3D%20328.48)
The minimum score needed to be considered for admission to Stanfords graduate school is 328.48.