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MrRissso [65]
3 years ago
10

A family room has a circular rug with a radius of 7 m .

Mathematics
1 answer:
irina [24]3 years ago
8 0

Answer:

153.94m²

plz mark me as brainliest :)

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25/3 ÷ x = 7/3 ÷8.1<br><br> I don't get it, what's the answer??
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Answer:

x=28.93(rounded) x=28.929(not rounded)

Step-by-step explanation:

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A certain brand of jelly beans are made so that each package contains about the same number of beans. The filling procedure is n
pantera1 [17]

Answer:

p=0.063

Step-by-step explanation:

Let X be number of the certain brand of jelly beans that are made so that each package contains about the same number of beans.

X is N(375, 8)

YOu are collecting a sample size of

n = 8

Findings from the sample

\bar x =370\\

H_0: \bar x =375\\H_a: \bar x

(Left tailed test at 5% level)

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Mean difference = -5

Std error = \frac{8}{\sqrt{8} } =2.828

Test statistic t = mean diference / std error = \frac{-5}{2.828} \\=-1.768

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3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST!!
vampirchik [111]

Answer:

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Step-by-step explanation:

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A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec
zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

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