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soldier1979 [14.2K]
3 years ago
11

Evaluate 9 √9. A 27 B √27 C 81 D 243

Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

Answer: 27

Step-by-step explanation:

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Mike is a car salesman. He earns $200 for every car he sells plus a 3% commission. If Mike sells 3 cars in one week for a total
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<span>For every car Mike earns------------------ >$200 plus 3% commission</span>

 3 cars----------------- > $200*3+$32,343*0.03=600+970.29=$1570.29

 Total earnings for a week is $1570.29

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What is 10/15 the same as
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If you simplify it, it would be that same as 2/3.
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The probability of getting a 4- bedroom home with a open porch based off the table.
AleksandrR [38]
All you have to do is multiply 1/3 (the chance of getting a 4 bedroom home) times 1/2 (the chance of getting an open porch). The answer is a 1/6 chance, as you don’t have to do anything with the kitchens because the question doesn’t specify to.

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3 years ago
If the circumference of a circle is 82p , then the value of ‘r’ is
Andrews [41]

Answer:

41cm

Step-by-step explanation:

The circumference of a circle is 82π

Therefore r can be calculated as follows

2 × π × r= 82× π

2πr= 82π

r = 82π/2π

r= 41

Hence r is 41cm

8 0
2 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
3 years ago
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