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3 years ago

9

Please Help.(picture below) 30 points

2 answers:

Sveta_85 [38]3 years ago

8 0

Answer = B = 376 degrees - 3x

Crazy boy [7]3 years ago

4 0

B: 376°

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F(x) x^2-2x+3= -2x+ 28

Aleksandr-060686 [28]

Answer:

x₁ = - 5, x₂ = 5

Step-by-step explanation:

x^2 + 3 = 28

x^2 = 28 - 3

x^2 = 25

x = ± 5

x = - 5

x = 5

6 0

3 years ago

Point A is located at (1, 5), and point M is located at (−1, 6). If point M is the midpoint of segment AB, find the location of

sashaice [31]

Ans: B=(-3, 7)

Step by step explanation:

7 0

3 years ago

Please help 49÷k –3=46

Andreas93 [3]

$\frac{49}{k} -3 = 46$
$\frac{49}{k} = 49$ . . . . add 3
$\frac{49}{49} = k$ . . . . multiply by $\frac{k}{49}$

k = 1

4 0

3 years ago

Simplify the number using the imaginary unit I. sqrt-25<br> a.-5t<br> b.5i<br> c.-5<br> d.5

pentagon [3]

The answer to this question is: B;5i

4 0

3 years ago

Read 2 more answers

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

So

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

3 0

3 years ago